Table of contents |
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Introduction |
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Formulas Used |
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Types of Train Problems |
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Things to Remember |
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Solved Examples |
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1. Speed of the Train
2. Two Trains Moving in Opposite Directions
If the length of two trains is given, say a and b, and the trains are moving in opposite directions with speeds of x and y respectively, then
3. Two Trains Moving in the Same Direction
If the length of two trains is given, say a and b, and they are moving in the same direction, with speeds x and y respectively, then
4. Ratio of Speeds Using Time After Crossing
When the starting time of two trains is the same from x and y towards each other, and after crossing each other, they take t1 and t2 time in reaching y and x respectively, then
Ratio between the speed of two trains = √t2: √t1
5. Meeting Point from Station X
If two trains leave x and y stations at times t1 and t2 respectively and travel with speeds L and M respectively, then the distance from x, where the two trains meet, is =
6. Rest Time per Hour
The average speed of a train without any stoppage is x, and with the stoppage, it covers the same distance at an average speed of y, then Rest Time per hour =
7. Crossing Time for Equal Length Trains (Opposite Directions)
If two trains of equal length and different speeds take t1 and t2 time to cross a pole, then the time taken by them to cross each other if the train is moving in the opposite direction =
8.Crossing Time for Equal Length Trains (Same Direction)
If two trains of equal lengths and different speeds take t1 and t2 time to cross a pole, then the time taken by them to cross each other if the train is moving in the same direction =
1. Crossing a Stationary Object
2. Crossing Another Train / Platform
Concept: Train covers the sum of lengths; relative speed depends on direction.
Example: Two trains (100 m at 36 km/h, 200 m at 54 km/h) moving in opposite directions. Calculate time taken to cross each other
3. Equation-Based Problems
Concept: Information from two cases is used to form equations.
Example: A train crosses a pole in 8 seconds and a platform of 160 m in 24 seconds. Find train length and speed.
Sol: Let the train length = L, and speed = S.
From pole:
L ÷ S = 8 ⟹ L = 8S
From platform:
(L + 160) ÷ S = 24
Substituting L = 8S:
(8S + 160) ÷ S = 24
⟹ 8S + 160 = 24S
⟹ 16S = 160
⟹ S = 10 m/s = 36 km/h
Thus, L = 80 m.
1. Always remember the two objects
Train vs pole/man → distance = length of train
Train vs platform → distance = length of train + length of platform
Train vs train → distance = sum of train lengths
2. Relative speed matters
Opposite directions → add speeds
Same direction → subtract speeds
3. Always remember the conversions
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1. What are the basic concepts involved in solving train problems? | ![]() |
2. How do you calculate the time taken for two trains to cross each other? | ![]() |
3. What is the role of length in train problems, and how is it used in calculations? | ![]() |
4. Can you explain how to approach problems involving trains moving in opposite directions? | ![]() |
5. What strategies can be used to solve complex train problems efficiently? | ![]() |