Class 5 Maths - Area and its Boundary - CBSE Worksheets Solutions - 1

Solve the following Questions.

Q1: What is the area of this rectangular field?

Sol:

Length of Rectangle = 100 m

Breadth of rectangle = 50 m

Area of Rectangle = Length x Breadth

= 100 m x 50 m = 5000 m²

Q2: Find the total boundary of the given piece A?

Sol: 
Perimeter of Rectangle = 2(L+ B)
= 2(5 + 6) = 2 x 11 = 22 cm

Q3: Find the perimeter of the given shape made up by the equilateral triangles?

Sol: In the given figure, we can see that there are 5 equilateral triangle 

And Triangle has 3 sides 

Perimeter of One triangle = sum of all sides = 4 cm + 4 cm + 4 cm = 12 cm

Perimeter of 5 Triangles will be = 12 x 5 = 60 cm

But we can see 2 sides are overlapped and we count just outer sides in perimeter so 60 cm - ( 2 x 4) = 60 cm - 8 cm = 52 cm

Q4: The fencing of a square garden is 120 cm long. How long is one side of the  garden?

Sol: Fencing of a square garden ( also called perimeter ) = 120 cm

Perimeter = Sum of all 4 sides ( or 4 x side) 

120 = 4  x side

Side = 120 / 4 = 30 cm

Q5: Which garden's area is bigger and by how much?

Sol: Formula of Area of Rectangle = Length x Breadth 

Area of Garden A = 30 m x 20 m = 600 m²

Area of Garden B = 40 m x 22 m = 880 m²

Difference between Area of Garden A and B =  880 m²- 600 m² = 280 m²

Garden B is bigger by 280m².

Q6: Can you find the missing variables?

Sol: Area = L x B 
55 m²= 11 m x B 
55 m² / 11 m = B
5 m = B
(i)Breadth = 5m

Perimeter = 2 ( L + B)
= 2 ( 11 + 5)
= 2 x 16 = 32 m
(ii) Perimeter = 32 m

Q7: A thin wire 120 cm long is formed into a rectangle. If the length of this rectangle is 40 cm. what is its width?

Sol: In the given the question , it 120 cm is the boundary that is mentioned which is called Perimeter
Length of Rectangle = 40 cm 
P = 2 (L + B )
120 cm = 2 ( 40 + B) 
120 / 2 = 40 + B 
60 - 40 = B
20 cm = B
Breadth of Rectangle = 20 cm

Q8: Divya needs a long ribbon to decorate a card of length  80 cm and breadth 100 cm. How long ribbon will she need if she wants to put the ribbon along the a border of the card.

Sol: Length of the card (l) = 80 cm
Breadth of the card (b) = 100 cm
To put the ribbon along the border, we need to find the perimeter of the rectangle.

Perimeter of a rectangle is given by:

$Perimeter\; =\; 2\; \times \; (l\; +\; b)$Perimeter=2×(l+b)
=2×(80+100)
=2×180
$=\; 360\; \backslash ,\; cm$=360cm

Thus, Divya needs 360 cm of ribbon to decorate the card.

Q9: Akhil plSol to decorate his room wall with square charts. Each side of the chart is 20 cm. The wall is 320 cm in length and 180 cm wide. How many charts will he need?

Sol:  Length of the wall (L) = 320 cm

Breadth of the wall (B) = 180 cm

Side of each square chart (s) = 20 cm

Number of charts along the length of the wall:

$\frac{}{}\backslash frac\{\backslash text\{Length\; of\; the\; wall\}\}\{\backslash text\{Side\; of\; the\; square\; chart\}\}$Side of the square chartLength of the wall$=\frac{320}{20}=16=\; \backslash frac\{320\}\{20\}\; =\; 16$

Number of charts along the breadth of the wall:

$\frac{}{}\backslash frac\{\backslash text\{Breadth\; of\; the\; wall\}\}\{\backslash text\{Side\; of\; the\; square\; chart\}\}$Side of the square chartBreadth of the wall$=\frac{180}{20}=9=\; \backslash frac\{180\}\{20\}\; =\; 9$

Total number of charts needed:

$16\times 9=14416\; \times \; 9\; =\; 144$

Thus, Akhil will need 144 square charts to decorate his wall

Q10: Meera wants to put a decorative border around a square-shaped garden. Each side of the garden is 25 meters long. How much fencing will she need to enclose the garden completely?

Sol: Side of the square garden (s) = 25 meters

Perimeter of a square is given by:

$Perimeter=4\times$side $=\; 4\; \times \; 25$=4×25$=\; 100\; \backslash ,\; meters$=100meters

Thus, Meera will need 100 meters of fencing to enclose the garden.