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GATE Life Science Mock Test- 5 (Botany & Zoology) - GATE Life Sciences MCQ


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30 Questions MCQ Test GATE Life Sciences 2026 Mock Test Series - GATE Life Science Mock Test- 5 (Botany & Zoology)

GATE Life Science Mock Test- 5 (Botany & Zoology) for GATE Life Sciences 2025 is part of GATE Life Sciences 2026 Mock Test Series preparation. The GATE Life Science Mock Test- 5 (Botany & Zoology) questions and answers have been prepared according to the GATE Life Sciences exam syllabus.The GATE Life Science Mock Test- 5 (Botany & Zoology) MCQs are made for GATE Life Sciences 2025 Exam. Find important definitions, questions, notes, meanings, examples, exercises, MCQs and online tests for GATE Life Science Mock Test- 5 (Botany & Zoology) below.
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GATE Life Science Mock Test- 5 (Botany & Zoology) - Question 1

Directions: A portion of the sentence or the whole sentence is highlighted. Below the sentence are four alternatives for rephrasing the highlighted section. Option (1) restates the original phrasing; the remaining three options are different. If you believe the original phrasing creates a more effective sentence than any of the alternatives, choose option (1). Otherwise, select the most suitable option from the other choices.

Regarding the delivery of a message that expresses uncertainty, he certainly delivers an unexpected outcome.

Detailed Solution for GATE Life Science Mock Test- 5 (Botany & Zoology) - Question 1

It corrects the error of gerund. 'Comes to delivering a message' is the correct usage. Here, the verb is being used as a noun, so the gerund form will be used.

GATE Life Science Mock Test- 5 (Botany & Zoology) - Question 2

Instructions: In the subsequent question, a specific relationship exists between the two words presented on one side of the notation : : and another word is to be identified from the provided options, which shares the same relationship with this new word as the words in the original pair do. Select the appropriate option.

Monday : Saturday : : Thursday : ?

Detailed Solution for GATE Life Science Mock Test- 5 (Botany & Zoology) - Question 2

Second is five days ahead of the first.

GATE Life Science Mock Test- 5 (Botany & Zoology) - Question 3

She observed me for a long ______________.

Detailed Solution for GATE Life Science Mock Test- 5 (Botany & Zoology) - Question 3

'Before' and 'Back' are also used in reference to time; however, only 'ago' is in reference to present time, which is the context here.

GATE Life Science Mock Test- 5 (Botany & Zoology) - Question 4

A whisky bottle holds 3/4th whisky, with the remainder being water. What volume of the mixture should be removed and replaced with an equal amount of water in order to achieve a composition of half whisky and half water?

Detailed Solution for GATE Life Science Mock Test- 5 (Botany & Zoology) - Question 4

Percentage of whisky in mixture = 75%
Percentage of whisky in water = 0%

Therefore, mixture and water should be mixed in the ratio of 2 : 1.
or,
We need to replace 1/3rd or  of the mixture with water.

GATE Life Science Mock Test- 5 (Botany & Zoology) - Question 5

A tank can be filled by two pipes, P and Q, in 6 hours and 9 hours, respectively, while another pipe, R, can empty the tank in 12 hours. Initially, pipes P and R are opened together for 4 hours. After this, pipe P is turned off, and pipe Q is turned on. Following 6 additional hours, pipe R is turned off. What is the total time taken to completely fill the tank (in hours)?

Detailed Solution for GATE Life Science Mock Test- 5 (Botany & Zoology) - Question 5

Pipes P, Q, and R have rates of filling/emptying the tank as follows:

  • P fills the tank at the rate of 1/6 per hour.
  • Q fills the tank at the rate of 1/9 per hour.
  • R empties the tank at the rate of 1/12 per hour.

Step 1: For the first 4 hours, pipes P and R are open:
Net rate = (1/6 - 1/12) = 1/12 per hour.
Volume filled in 4 hours = 4 x (1/12) = 1/3 of the tank.

Step 2: For the next 6 hours, pipes Q and R are open:
Net rate = (1/9 - 1/12) = 1/36 per hour.
Volume filled in 6 hours = 6 x (1/36) = 1/6 of the tank.

Total volume filled after 10 hours (4+6) = 1/3 + 1/6 = 1/2 of the tank.

Step 3: After 10 hours, only pipe Q is open (R is turned off).
Pipe Q fills the remaining half of the tank at the rate of 1/9 per hour.

Time taken to fill the remaining half = (1/2) / (1/9) = 4.5 hours.

Total time taken to fill the tank = 10 + 4.5 = 14.5 hours.

GATE Life Science Mock Test- 5 (Botany & Zoology) - Question 6

Which coordination complex exhibits a distorted octahedral geometry?
(Given: Atomic numbers of V: 23, Mn: 25, Ni: 28, Cu: 29)

GATE Life Science Mock Test- 5 (Botany & Zoology) - Question 7

Given the standard electrode potentials:
Fe2 2e– → Fe E° = -0.440V
Fe3 3e– → Fe E° = -0.036V
What is the standard electrode potential (Eo) for the reaction Fe3 e → Fe2 ?

Detailed Solution for GATE Life Science Mock Test- 5 (Botany & Zoology) - Question 7

Since EMF of the cell is not additive, therefore we can use the Gibbs energy as:

GATE Life Science Mock Test- 5 (Botany & Zoology) - Question 8

Which of the following statements regarding the diborane molecule is incorrect?

*Multiple options can be correct
GATE Life Science Mock Test- 5 (Botany & Zoology) - Question 9

Compound X yields alcohol P as the predominant product in the reaction depicted below. Which of the following option(s) could represent X?

*Answer can only contain numeric values
GATE Life Science Mock Test- 5 (Botany & Zoology) - Question 10

How many radial node(s) exist for the valence orbital of the U(III) ion? Provide your answer as an integer.
(Note: The atomic number of U is 92)


*Answer can only contain numeric values
GATE Life Science Mock Test- 5 (Botany & Zoology) - Question 11

Eº = 1.10 V for the following cell reaction:

For this reaction, the equilibrium constant is y × 1037 at 298 K. The value of y is _____ (rounded off to two decimal places). 
(Given: F = 96485 C molˉ1, R = 8.314 J K ˉ1 molˉ1)


GATE Life Science Mock Test- 5 (Botany & Zoology) - Question 12

In a Tobacco callus, which of the following will promote the differentiation of shoots?

GATE Life Science Mock Test- 5 (Botany & Zoology) - Question 13

The diagram illustrates an unexpanded plant cell located within a hypocotyl, highlighting the arrangement of cellulose microfibrils on its cell wall. Which of the following shapes is most likely to be formed as a result of the cell's expansion, assuming the arrangement of the cellulose fibrils remains unchanged?

*Answer can only contain numeric values
GATE Life Science Mock Test- 5 (Botany & Zoology) - Question 14

In a species where 2n = 16 chromosomes, what is the total number of chromosomes in a cell of a double monosomic individual?


*Answer can only contain numeric values
GATE Life Science Mock Test- 5 (Botany & Zoology) - Question 15

In a diploid organism where 2n = 8, the ovule experiences double fertilization. If the pollen is sourced from an individual exhibiting meiotic nondisjunction, what will be the chromosome count of the zygote?


GATE Life Science Mock Test- 5 (Botany & Zoology) - Question 16

Establish the correct pairs between Group I and Group II concerning the substances that disrupt oxidative phosphorylation.

GATE Life Science Mock Test- 5 (Botany & Zoology) - Question 17

Cimeric genes incorporating the CAMV353 promoter and coding for human serum albumin (HSA) were successfully transferred to yield

Detailed Solution for GATE Life Science Mock Test- 5 (Botany & Zoology) - Question 17

This is the producer to produce human serum albumin (HAS). Chimeric genes having CaMV35S serves as promoter. The secretion of protein was achieved by using either the human prepro sequence or the signal sequence from extracellular PR-S protein from tobacco. HAS was secreted intransgenic leaf tissue.

GATE Life Science Mock Test- 5 (Botany & Zoology) - Question 18

Which category is known as the "Gem of the plant kingdom"?

Detailed Solution for GATE Life Science Mock Test- 5 (Botany & Zoology) - Question 18

Chrysophytes or golden algae group is referred to as "Jewel of plant kingdom" found usually in fresh water; typically Prymnesium parvum is utilised to kill fishes. Their cell composed of specialised flagella. Their active flagella is oriented towards their moving direction.

GATE Life Science Mock Test- 5 (Botany & Zoology) - Question 19

Pair the items from the list below:

Detailed Solution for GATE Life Science Mock Test- 5 (Botany & Zoology) - Question 19

Hairless cat is an example of substantive discontious variation. These variation is responsible for formation of new species and organism called mutant. These influence shape, colour, size, etc. Polyltdactyly is the example of meristic discontinuous variation. These affect no. of parts and responsible for formation of new species. Number of grains in an ear of wheat is the example of continuous meristic variation. These also affect the number of parts but these are the fluctuating variation and cannot give rise to new species. Star and asteroid traits in Drosophila is the example of pseudoalleles where genes are present side by side and they produce related phenotypes. These are distinguished from true alleles through rare crossing. Antirrhinum majus is the example of incomplete dominance where the phenotypic and genotypic ratio is same in F2 generation i.e. 1 : 2 : 1.

GATE Life Science Mock Test- 5 (Botany & Zoology) - Question 20

Retroviruses encode reverse transcriptases. The sole enzyme found in mammalian cells that exhibits reverse transcriptase-like activity is

GATE Life Science Mock Test- 5 (Botany & Zoology) - Question 21

Which ONE of the following types of leucocytes possesses phagocytic properties and features a clear cytoplasm?

GATE Life Science Mock Test- 5 (Botany & Zoology) - Question 22

Which option represents a flawless correspondence?

Detailed Solution for GATE Life Science Mock Test- 5 (Botany & Zoology) - Question 22

Perfect match: Autecology - interrelationship of an organism to the environment. Autecology is the branch of ecology that concerns with biological relationship between a particular organism or a particular species and its surroundings or environment.

*Answer can only contain numeric values
GATE Life Science Mock Test- 5 (Botany & Zoology) - Question 23

The total count of complementary determining regions (CDRs) present in the functional configuration of an IgM antibody is _____


GATE Life Science Mock Test- 5 (Botany & Zoology) - Question 24

The polymerase chain reaction is considered a groundbreaking technology due to all of the following reasons, except

Detailed Solution for GATE Life Science Mock Test- 5 (Botany & Zoology) - Question 24

Polymerase chain reaction is the biochemical technology in the molecular biology to intensify one or more copies of a segment of DNA across various orders of magnitude forming numerous copies of specific DNA sequences. Polymerase chain reaction is regarded as the revolutionary technology as all of the following, except it causes direct formation of the synthetic gene which did not exist before.

GATE Life Science Mock Test- 5 (Botany & Zoology) - Question 25

Pair the items listed below:

GATE Life Science Mock Test- 5 (Botany & Zoology) - Question 26

Both tarantulas and mosquitoes are classified under the phylum Arthropoda. Which ONE of the following accurately indicates the number of legs found in each of them, respectively?

GATE Life Science Mock Test- 5 (Botany & Zoology) - Question 27

Pair the subcellular organelles listed in Column I with their corresponding functions found in Column II.

GATE Life Science Mock Test- 5 (Botany & Zoology) - Question 28

Signal transduction occurs when an extracellular signaling molecule activates a receptor on the cell surface, thereby modifying intracellular molecules and eliciting a response. This process comprises two stages:
i. A signaling molecule activates a specific receptor protein located on the cell membrane.
ii. The 2nd messenger transmits the signal into the cells, leading to a physiological response.

The mechanism of signal transduction by steroid hormones differs from that of amine and peptide hormones because

Detailed Solution for GATE Life Science Mock Test- 5 (Botany & Zoology) - Question 28

The process of signal transduction by steroid hormones varies from amine and peptide hormones because they attach to cytoplasmic or nuclear receptor & affect gene expression. Steroid hormone receptors are present on plasma membrane in cytosol & also in target cell's nucleus. They are usually intracellular receptors & starts signal transduction for steroid hormones that causes changes in gene expression over the time.

*Multiple options can be correct
GATE Life Science Mock Test- 5 (Botany & Zoology) - Question 29

Which of the following methods is/are employed to ascertain the three-dimensional configuration of proteins?

*Answer can only contain numeric values
GATE Life Science Mock Test- 5 (Botany & Zoology) - Question 30

An enzyme exhibiting Michaelis-Menten kinetics facilitates the transformation of 35 μM of substrate into product at a reaction velocity of 10 μM s-1. The Km and kcat values for the substrate are 14 μM and 500 s-1, respectively. The total concentration of enzyme used in the reaction is _____nM. 


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