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DSE Odisha TGT Science PCM Mock Test - 2 - OTET MCQ


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30 Questions MCQ Test DSE Odisha TGT Mock Test Series 2025 - DSE Odisha TGT Science PCM Mock Test - 2

DSE Odisha TGT Science PCM Mock Test - 2 for OTET 2025 is part of DSE Odisha TGT Mock Test Series 2025 preparation. The DSE Odisha TGT Science PCM Mock Test - 2 questions and answers have been prepared according to the OTET exam syllabus.The DSE Odisha TGT Science PCM Mock Test - 2 MCQs are made for OTET 2025 Exam. Find important definitions, questions, notes, meanings, examples, exercises, MCQs and online tests for DSE Odisha TGT Science PCM Mock Test - 2 below.
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DSE Odisha TGT Science PCM Mock Test - 2 - Question 1

Which sport is associated with the term "home run"?

Detailed Solution for DSE Odisha TGT Science PCM Mock Test - 2 - Question 1

A "home run" is scored in baseball when a batter hits the ball out of the playing field, allowing them to circle all the bases and reach home plate without being put out.

DSE Odisha TGT Science PCM Mock Test - 2 - Question 2

The Northern Plains are primarily formed by the alluvial sediments carried by which rivers?

Detailed Solution for DSE Odisha TGT Science PCM Mock Test - 2 - Question 2

The Northern Plains in India are primarily formed by the alluvial sediments carried by rivers like the Indus, Ganga, and Brahmaputra. These plains stretch for approximately 3,200 kilometers from east to west.

DSE Odisha TGT Science PCM Mock Test - 2 - Question 3

Which state is known for being the largest producer of rice in India?

Detailed Solution for DSE Odisha TGT Science PCM Mock Test - 2 - Question 3
West Bengal is known for being the largest producer of rice in India.
DSE Odisha TGT Science PCM Mock Test - 2 - Question 4

Who became the first Indian male to win an individual gold medal at the Asian Games?

Detailed Solution for DSE Odisha TGT Science PCM Mock Test - 2 - Question 4

The first Indian male to win an individual gold medal at the Asian Games was Sachin Nag  He won the gold medal in swimming (100m freestyle) at the 1951 Asian Games held in New Delhi, making him the first Indian male to achieve this feat.
Therefore, the correct answer is option A

DSE Odisha TGT Science PCM Mock Test - 2 - Question 5

What is the significance of the Tropic of Cancer in relation to India?

Detailed Solution for DSE Odisha TGT Science PCM Mock Test - 2 - Question 5

Correct option is A. It divides India into northern and southern parts
The Tropic of Cancer passes through the central part of India, approximately dividing the country into two halves, namely the northern and southern halves. This line of latitude is significant for India's geography and climate, as it marks the northern boundary of the tropical region and influences various climatic phenomena such as the monsoon. However, it does not act as the standard Time Meridian of India, nor is it the southernmost point of the Indian mainland, nor does it serve as the northern boundary of India.

DSE Odisha TGT Science PCM Mock Test - 2 - Question 6

Odisha is the third largest produce of ...............

Detailed Solution for DSE Odisha TGT Science PCM Mock Test - 2 - Question 6

Odisha, after M.P. and Chatisgarh, is the third largest producer of kendu leaf. Odisha produces roughly 4.5 to 5 lakh quintal of Bidi Leaf every year, accounting for about 20% of the country's total production. Odisha's Tendu (kendu) leaf is unique in that it is processed, whereas the rest of India produces it in phal form.

DSE Odisha TGT Science PCM Mock Test - 2 - Question 7
Who wrote the book India-From Midnight to the Millennium?
Detailed Solution for DSE Odisha TGT Science PCM Mock Test - 2 - Question 7
Sashi Tharoor, former UN diplomat and Member of Parliament, wrote India-From Midnight to the Millennium, a compelling exploration of India's journey post-independence.
DSE Odisha TGT Science PCM Mock Test - 2 - Question 8

Direction: If a Paper (Transparent Sheet) is folded in a manner and a design or pattern is drawn. When unfolded this paper appears as given below in the answer figure. Choose the correct answer figure given below.

If the following pattern is drawn in a transparent square sheet and folded along the dotted lines, how does it appear?

Question Figure

Answer figure

Detailed Solution for DSE Odisha TGT Science PCM Mock Test - 2 - Question 8

DSE Odisha TGT Science PCM Mock Test - 2 - Question 9

Which answer figure will complete the pattern in the question figure?

Detailed Solution for DSE Odisha TGT Science PCM Mock Test - 2 - Question 9

DSE Odisha TGT Science PCM Mock Test - 2 - Question 10

Directions: Each of the following consists of a question and two statements numbered I and II given below it. You have to decide whether the data provided in the statements are sufficient to answer the question.

Which statement is required to derive the conclusion - 'No Player is a Champion'?
Statement I:
All Stars are Goalkeepers.
Statement II: No Champion is a Player.

Detailed Solution for DSE Odisha TGT Science PCM Mock Test - 2 - Question 10

Checking Statement I:

Since there is no data given about Player and Champion, therefore, No player is Champion can not be derived.

Clearly, Statement I alone is not sufficient to answer the question.

Checking Statement II:

Statement II is the converse statement of the required conclusion.

Clearly, Statement II alone is sufficient to answer the question.

Hence, Option B is correct.

DSE Odisha TGT Science PCM Mock Test - 2 - Question 11

A computer cannot “boot” if it does not have the

Detailed Solution for DSE Odisha TGT Science PCM Mock Test - 2 - Question 11

Why a computer cannot "boot" without an operating system:



  • Definition of "boot": Booting refers to the process of starting up a computer and loading the necessary software to make it ready for use.

  • Primary functions of an operating system: The operating system (OS) is responsible for managing all the hardware and software resources of a computer, and it performs several essential functions during the boot process:


    • Hardware initialization: The OS initializes and configures all the hardware components of the computer, such as the processor, memory, storage devices, and input/output devices.

    • Device drivers: The OS loads the necessary device drivers, which are software programs that enable communication between the operating system and the hardware devices.

    • File system management: The OS mounts the file system, allowing it to access and organize the files stored on the storage devices.

    • Process management: The OS creates and manages processes, which are the executing instances of programs, allowing multiple programs to run concurrently.

    • User interface: The OS provides a user interface that allows users to interact with the computer, whether through a graphical interface or a command-line interface.


  • Boot process: The boot process involves several steps, including:


    • Power-on self-test (POST): The computer's firmware (BIOS or UEFI) performs a diagnostic test to check the hardware components and ensure they are functioning properly.

    • Bootloader: The firmware locates and executes the bootloader, which is responsible for loading the operating system into memory.

    • Operating system: The bootloader transfers control to the operating system, allowing it to take over and continue the boot process.


  • Conclusion: Without an operating system, the computer would not have the necessary software to manage its hardware resources, provide a user interface, or execute programs. Therefore, a computer cannot "boot" without an operating system.

DSE Odisha TGT Science PCM Mock Test - 2 - Question 12

Layer one of the OSI model is

Detailed Solution for DSE Odisha TGT Science PCM Mock Test - 2 - Question 12
Layer one of the OSI model is the Physical layer.
The Physical layer is responsible for the actual transmission of data bits over a physical medium. It deals with the physical characteristics of the communication medium and the electrical, mechanical, and functional specifications of the devices used to transmit data.
Key points about the Physical layer:
- It is the lowest layer in the OSI model and is concerned with the physical transmission of data.
- The Physical layer defines the physical and electrical properties of the transmission medium, such as cables, connectors, and signaling methods.
- It handles the conversion of digital data into a physical signal for transmission and vice versa.
- It defines the protocols for data encoding, modulation, and synchronization.
- It deals with the transmission of raw bits and does not concern itself with the content or structure of the data being transmitted.
- It ensures that the data is sent and received reliably, without errors or loss.
- Examples of devices that operate at the Physical layer include network interface cards (NICs), cables, hubs, repeaters, and modems.
- The Physical layer provides the foundation for higher layers in the OSI model to transmit data.
In summary, the Physical layer is responsible for the physical transmission of data and defines the specifications of the transmission medium and devices used for communication. It is the first layer in the OSI model and plays a crucial role in ensuring reliable data transmission.
DSE Odisha TGT Science PCM Mock Test - 2 - Question 13

Which is the place where the child's 'cognitive' development is defined in the best way?  

Detailed Solution for DSE Odisha TGT Science PCM Mock Test - 2 - Question 13

School is a place designed to provide an adequate learning environment. In school, the opportunity a child gets to learn affects his cognitive development. The more opportunities a child gets, the better his cognition because he/she will be able to add to his/her mental capacities by learning through these opportunities. In school, during teaching-learning, many new concepts form, many new ideas develop, and many other mental processes take place.

DSE Odisha TGT Science PCM Mock Test - 2 - Question 14

The instructions provided by the teacher must be based on a child's

Detailed Solution for DSE Odisha TGT Science PCM Mock Test - 2 - Question 14

The instructions of a teacher must be based on the child's abilities, aptitude and interest. His ability to grasp and apply things, his natural ability to justify learning and his interest to learn a particular thing could decide the teaching strategies, as the education these days has become more child-centered. The teacher must be aware of the child's abilities, aptitude, and interest, which is possible only through proper evaluation.

DSE Odisha TGT Science PCM Mock Test - 2 - Question 15

A double convex lens made of glass of refractive index 1.56 has both radii of curvature of magnitude 20cm. If an object is placed at a distance of 10cm from this lens, the position of the image formed is

Detailed Solution for DSE Odisha TGT Science PCM Mock Test - 2 - Question 15

Here, R1 = 20 cm, R2 = −20 cm, u = −10 cm and μ = 1.56
Using lens make'rs formula,

Now, from lens equation,

Since v is negative, the image will be formed on the same side as that of object.

DSE Odisha TGT Science PCM Mock Test - 2 - Question 16

It is necessary to use satellites for long distance TV transmission because

Detailed Solution for DSE Odisha TGT Science PCM Mock Test - 2 - Question 16

TV signals being of high frequency are not reflected by the ionosphere. Therefore, to reflect these signals, satellites are needed. That is why, satellites are used for long distance TV transmission.
 Most long-distance shortwave (high frequency) radio communication—between 3 and 30 MHz—is a result of skywave propagation.
This 3-30 MHz is a range of frequencies which are used in sky waves propagation so that the ionosphere is capable of reflecting it.

DSE Odisha TGT Science PCM Mock Test - 2 - Question 17

The direction of propagation of an electromagnetic plane wave is

Detailed Solution for DSE Odisha TGT Science PCM Mock Test - 2 - Question 17

The direction of propagation of the electromagnetic wave is always perpendicular to the plane in which
So, the direction of the propagation of the wave, 
Hence, option B is the correct answer.

DSE Odisha TGT Science PCM Mock Test - 2 - Question 18

An electric bulb is rated 220 V and 100 W. Power consumed by it operated on 110 V is

Detailed Solution for DSE Odisha TGT Science PCM Mock Test - 2 - Question 18

Power, P= V2/R​
R= V2/P​
R=220×220/100 ​=484Ω
The current flow in the circuit,
i= V′/R​ (V′= supplied voltage)
i=110/484​=0.2272A
The voltage drop across the bulb is 110V
The power consumed by the bulb,
Pb​=V2/R​=110×110​/484
Pb​=25W
The correct option is C.
 

DSE Odisha TGT Science PCM Mock Test - 2 - Question 19

The first use of quantum theory to explain the structure of atom was made by :

Detailed Solution for DSE Odisha TGT Science PCM Mock Test - 2 - Question 19

Bohr's theory was based upon some postulations of classical physics and some postulations of the newly proposed quantum theory of Planck. 

DSE Odisha TGT Science PCM Mock Test - 2 - Question 20

The light radiations with discrete quantities of energy are called ___________ .

Detailed Solution for DSE Odisha TGT Science PCM Mock Test - 2 - Question 20

A photon is the quantum of electromagnetic radiation. The term quantum is the smallest elemental unit of a quantity, or the smallest discrete amount of something. Thus, one quantum of electromagnetic energy is called a photon. The plural of quantum is quanta.

DSE Odisha TGT Science PCM Mock Test - 2 - Question 21

Which is not anomalous pair of elements in the Medeleeves periodic table -

Detailed Solution for DSE Odisha TGT Science PCM Mock Test - 2 - Question 21

In Mendeleev’s periodic table, the elements are arranged in the increasing order of their atomic masses. In some places, this order has been ignored.

(a) Ar and K:  The atomic mass of argon is 40 and that of potassium is 39, But argon is placed beforepotassium in the periodic table.

(b) Co and Ni: The positions of cobalt and nickel are not in proper order. Cobalt (at. wt. = 59.9) is placed before nickel (at. wt. = 58.6).

(c) Te and I: Tellurium (at. wt. = 127.6) is placed before iodine (at. wt = 126.9).

(d) Thorium (at, wt. =232.12) is placed before protactinium (at. Wt = 231).

So, Al and Si is not the anomalous pair  of elements in the Mendeleev's periodic table.

DSE Odisha TGT Science PCM Mock Test - 2 - Question 22

Which of the following carbohydrates are branched polymer of glucose?

Detailed Solution for DSE Odisha TGT Science PCM Mock Test - 2 - Question 22

The correct answer is option B.
Amylopectin is insoluble in water and constitutes about 80−85% of starch. It is a branched-chain polymer of −D− glucose units in which chain is formed by C1−C4 glycosidic linkage whereas branching occurs by C1−C6 glycosidic linkage. Glycogen: The carbohydrates are stored in the animal body as glycogen. It is also known as animal starch because its structure is similar to amylopectin and is rather more highly branched.

DSE Odisha TGT Science PCM Mock Test - 2 - Question 23

lf En = total energy, Kn = kinetic energy, Vn = potential energy and rn = radius of the nth orbit, then based on Bohr’s theory, match the parameter in Column I with the values in Column II.

Detailed Solution for DSE Odisha TGT Science PCM Mock Test - 2 - Question 23





DSE Odisha TGT Science PCM Mock Test - 2 - Question 24

Given ΔH for the process Li(g) → Li+3(g) + 3e- is 19800 kJ/mole & IE1 for Li is 520 then IE2 & IE3 of Li+ are respectively (approx, value) :

Detailed Solution for DSE Odisha TGT Science PCM Mock Test - 2 - Question 24

IE1 + IE2 + IE3 = 19800
IE2 + IE3 = 19800 – 520
IE2 + IE3 = 19280

DSE Odisha TGT Science PCM Mock Test - 2 - Question 25

Calculate the Gibbs free energy for the reaction of conversion of ATP into ADP at 293 Kelvin the change in enthalpy is 19.07 Kcal and the change in entropy is 90 cal per Kelvin.

Detailed Solution for DSE Odisha TGT Science PCM Mock Test - 2 - Question 25

We have ΔG = ΔH – TΔS; by substituting ΔH = 19.07 kcal and ΔS = 90 cal/K, we get ΔG = 19.07 Kcal – 293(90 cal/K) = 19.07 Kcal – 26.37 Kcal = -7300 cal = -7.3 Kcal. The Gibbs free energy change is -7.3 Kcal.

DSE Odisha TGT Science PCM Mock Test - 2 - Question 26

Only One Option Correct Type

This section contains multiple choice questions. Each question has four choices (a), (b), (c) and (d), out of which ONLY ONE is correct.

Q.

Cl2 gas is passed into a solution containing KF, Kl and KBr, and CHCI3 is added. There is a colour in CHCI3 (lower) layer. It is due to 

Detailed Solution for DSE Odisha TGT Science PCM Mock Test - 2 - Question 26

Based on electro chemical series, oxidising power of
F2 > Cl2 > Br2 > I2

On passing Cl2 in to a solution containing KF, Kl and KBr,
2KBr + Cl2 → 2KCI + Br2 (orange)
2KI + Cl→ 2KCI + l2 (violet)
2KI + Br2 → 2KBr + l2 (violet)
Br2 formed also oxidises Kl to l2 (violet)

DSE Odisha TGT Science PCM Mock Test - 2 - Question 27

The unit of electrochemical equivalent is-

Detailed Solution for DSE Odisha TGT Science PCM Mock Test - 2 - Question 27

Z = w/it
w in gm
it in columb.
so z = gm/columb

DSE Odisha TGT Science PCM Mock Test - 2 - Question 28

A circle is drawn touching the x-axis and centre at the point which is the reflection of (a, b) in the line y – x = 0. The equation of the circle is

Detailed Solution for DSE Odisha TGT Science PCM Mock Test - 2 - Question 28

Radius of the circle = a 
and centre ≡ (b,a)
And circle is touching the x-axis.
The equation of the circle :
x2+y2−2bx−2ay+b= 0

DSE Odisha TGT Science PCM Mock Test - 2 - Question 29

If f(x) = x2 and g(x) = x are two functions from R to R then f(g(2)) is:

Detailed Solution for DSE Odisha TGT Science PCM Mock Test - 2 - Question 29

f(g(2)) compare f(gx) x=2
on comparing g(x)=x, g(2)=2
f(g(x)) = f(2) = x= 22= 4

DSE Odisha TGT Science PCM Mock Test - 2 - Question 30

A doctor is to visit a patient. From the past experience, it is known that the probabilities that he will come by train, bus, and scooter or by other means of transport are respectively 0.3, 0.2, 0.1 and 0.4. The probabilities that he will be late are 1/4 , 1/3 and 1/12, if he comes by train, bus and scooter respectively, but if he comes by other means of transport, then he will not be late. When he arrives, he is late. The probability that he comes by bus is:​

Detailed Solution for DSE Odisha TGT Science PCM Mock Test - 2 - Question 30

Let E1,E2,E3andE4 be the events that the doctor comes by train, bus, scooter and car respectively. Then,
P(E1)=3/10,P(E2)=1/5,P(E3)=1/10andP(E4)=2/5.
Let E be the event that the doctor is late. Then,
P(E/E1) = probability that the doctor is late, given that he comes by train
=1/4.
P(E/E2)= probability that the doctor is late, given that he comes by bus
=1/3.
P(E/E3)= probability that the doctor is late, given that the comes by scooter
=1/12.
P(E/E4)= probability that the doctor is late, given that that he comes by car
=0.
Probability that he comes by train, given that he is late
P(E2/E)
[P(E2).P(E/E2)]/[P(E1).P(E/E1)+P(E2).P(E/E2)+P(E3).P(E/E3)+P(E4).P(E/E40)][by Bayes's theorem]
[(1/5×1/3)]/(3/10×1/4)+(1/5×1/3)+(1/10×1/12)+(2/5×0)
=(3/40×120/18)=4/9
Hence, the required probability is 4/9.

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