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DSSSB PGT Physics Mock Test - 2 - DSSSB TGT/PGT/PRT MCQ


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30 Questions MCQ Test DSSSB PGT Mock Test Series 2025 - DSSSB PGT Physics Mock Test - 2

DSSSB PGT Physics Mock Test - 2 for DSSSB TGT/PGT/PRT 2025 is part of DSSSB PGT Mock Test Series 2025 preparation. The DSSSB PGT Physics Mock Test - 2 questions and answers have been prepared according to the DSSSB TGT/PGT/PRT exam syllabus.The DSSSB PGT Physics Mock Test - 2 MCQs are made for DSSSB TGT/PGT/PRT 2025 Exam. Find important definitions, questions, notes, meanings, examples, exercises, MCQs and online tests for DSSSB PGT Physics Mock Test - 2 below.
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DSSSB PGT Physics Mock Test - 2 - Question 1

Direction: Study the following information carefully to answer the given questions:

If 'A () B' means 'B is the mother of A'

If 'A of B' means 'B is the father of A'

If 'A ÷ B' means 'B is the sister of A'

If 'A × B' means 'B is the brother of A'

If 'A + B' means 'B is the daughter of A'

If 'A - B' means 'B is the son of A'

Q. If 'P of Q + R' is given, then which of the following is true?

Detailed Solution for DSSSB PGT Physics Mock Test - 2 - Question 1

'P of Q + R' means Q is the father of P, R is the daughter of Q.

Hence, R is the sister of P.

DSSSB PGT Physics Mock Test - 2 - Question 2

In SI unit the angular acceleration has unit of-

Detailed Solution for DSSSB PGT Physics Mock Test - 2 - Question 2

Angular acceleration. Angular acceleration is the rate of change of angular velocity. In three dimensions, it is a pseudovector. In SI units, it is measured in radians per second squared (rad/s2), and is usually denoted by the Greek letter alpha (α).

DSSSB PGT Physics Mock Test - 2 - Question 3

The coordinates of a moving particle at any time t are given by  and . The speed of the particle at time t is given by:

[AIEEE 2003]

Detailed Solution for DSSSB PGT Physics Mock Test - 2 - Question 3

DSSSB PGT Physics Mock Test - 2 - Question 4

A ball is thrown from a point with a speed v0 at an angle of projection θ. From the same point and at the same instant, a person starts running with a constant speed v0 / 2 to catch the ball. Will the person be able to catch the ball? If yes, what should be the angle of projection?

[AIEEE 2004]

Detailed Solution for DSSSB PGT Physics Mock Test - 2 - Question 4

For a person to catch the ball they should travel the same distance along the horizontal axis in time T.
Distance covered by person, R 


 

DSSSB PGT Physics Mock Test - 2 - Question 5

A uniform force of (3 i + j) N acts on a particle of mass 2 kg. Hence the particle is displaced from position (2 i + k) m to position ( 4 i + 3 j - k) m. The work done by the force on the particle is,

Detailed Solution for DSSSB PGT Physics Mock Test - 2 - Question 5

Uniform force acting = 3i + j N
Displacement done = (4-2)i + 3j + (-1-1)k
= 2i + 3j -2k
Thus total work done = F.s (dot product here)
We get W = 3 x 2 + 1 x 3 + 0 x -2
= 9J

DSSSB PGT Physics Mock Test - 2 - Question 6

The path of a projectile is 

Detailed Solution for DSSSB PGT Physics Mock Test - 2 - Question 6

The path of a projectile under the influence of gravity is a parabola. This is derived from the kinematic equations of motion in two dimensions:

  • The horizontal motion is uniform (constant velocity).
  • The vertical motion is uniformly accelerated (due to gravity).

Combining these motions, the equation of the trajectory is:

This equation represents a parabolic path, where θ is the angle of projection, u is the initial velocity, and g is the acceleration due to gravity.

Thus, the trajectory of a projectile is a parabola.

DSSSB PGT Physics Mock Test - 2 - Question 7

Three forces start acting simultaneously on a particle moving with velocity . These forces are represented in magnitude and direction by the three sides of a triangle ABC (as shown). The particle will now move with velocity    

   

[AIEEE 2003]

Detailed Solution for DSSSB PGT Physics Mock Test - 2 - Question 7

Resultant force is zero, as three forces on the particle can be represented in magnitude and direction by three sides of a       triangle in same order. Hence, by Newton's 2nd law 

Particle velocity  will be same

DSSSB PGT Physics Mock Test - 2 - Question 8

A block rests on a rough inclined plane making an angle of 30° with the horizontal. The coefficient of static friction between the block and the plane is 0.8. If the frictional force on the block is 10 N, the mass of the block (in kg) is (g = 10 m/s2

[AIEEE 2004]

Detailed Solution for DSSSB PGT Physics Mock Test - 2 - Question 8

Let mass of the block be m.

Frictional force in rest position F = mg sin 300

[This is static frictional force and may be less than the limiting frictional force]

DSSSB PGT Physics Mock Test - 2 - Question 9

After the body starts moving, the friction involved with motion is

Detailed Solution for DSSSB PGT Physics Mock Test - 2 - Question 9

When the body is in rest it is under static friction but when it starts moving (neither rolling nor sliding), the static friction slowly chngs to kinetic friction as the coefficient of static friction start decreasing and that of kinetic friction starts increasing. In case it starts rolling motion then the friction is rolling friction & if it slides then sliding fiction.

DSSSB PGT Physics Mock Test - 2 - Question 10

In an elastic collision in one dimension if a body A collides against the body B of equal mass at rest, then the body A will

Detailed Solution for DSSSB PGT Physics Mock Test - 2 - Question 10

Since collision is elastic and mass is same then after velocity exchange A body will stop and B will start moving with A's velocity in the same direction.

DSSSB PGT Physics Mock Test - 2 - Question 11

 In the given figure, what is the work done by the spring force?

Detailed Solution for DSSSB PGT Physics Mock Test - 2 - Question 11

We know that for a spring with spring constant k, work done by the spring when a compression or expansion is done of some length say x is ½ kx2
Also as the work done is in the opposite direction to that of force applied, we get the sign of the force to be negative.

DSSSB PGT Physics Mock Test - 2 - Question 12

Two identical thin uniform rods of length L each are joined to form T shape as shown in the figure. The distance of centre of mass from D is  

Detailed Solution for DSSSB PGT Physics Mock Test - 2 - Question 12


On solving we get 3L/4
 

DSSSB PGT Physics Mock Test - 2 - Question 13

A body of mass m moving at a constant velocity v hits another body of the same mass moving with a velocity v/2 but in the opposite direction and sticks to it. The common velocity after collision is 

Detailed Solution for DSSSB PGT Physics Mock Test - 2 - Question 13


Hence v = v/4
 

DSSSB PGT Physics Mock Test - 2 - Question 14

Newton's law of gravitation is called universal law because: 

Detailed Solution for DSSSB PGT Physics Mock Test - 2 - Question 14

Concept 

Newton's law of gravitation states "Every particle of matter in the universe attracts every other particle with a force that is directly proportional to the product of their masses and inversely proportional to the square of the distance between their centres."

Explanation 

Newton's law of gravitation can be represented mathematically as: F = G x (m1 x m2/ r2)

Where:

  • F is the force of attraction between the two bodies.
  • m1 and m2 are the masses of the two bodies.
  • r is the distance between the centres of the two bodies.
  • G is the gravitational constant, a proportional constant that in the SI system is approximately 6.674 x10-11N(m/kg)2.
  • So, if you have two bodies with masses m1 and m2, and they are separated by a distance r, then the force of gravity between them is directly proportional to the product of their masses and inversely proportional to the square of the distance between them,
  • Real-world applications of this law include everything from explaining the motion of planets in our solar system to the rolling of a ball down a hill. It's one of the cornerstones of classical physics and is essential in understanding the larger structure of the universe.

DSSSB PGT Physics Mock Test - 2 - Question 15

As observed from earth, the sun appears to move in an approximate circular orbit. For the motion of another planet like mercury as observed from earth, this would

Detailed Solution for DSSSB PGT Physics Mock Test - 2 - Question 15

Concept:

Newton's law of gravitation: The force of attraction between any objects in the universe is directly proportional to the product of their masses and inversely proportional to the square of the distance between them.

  • The force acts along the line joining the two bodies.
  • The gravitational force is a central force that is It acts along the line joining the centers of two bodies.
  • It is a conservative force. This means that the work done by the gravitational force in displacing a body from one point to another is only dependent on the initial and final positions of the body and is independent of the path followed.

Explanation:

  • The gravitational force on mercury due to the sun is very large than that due to the earth.
  • As observed from the earth, the sun appears to move around the earth in a circular orbit though, in reality, the earth moves around the sun due to gravitational force between them
  • All planets move around the sun due to the huge gravitational force of the sun acting on them.
  • Since the gravitational force on mercury due to the earth is smaller as compared to that on it due to the sun therefore it revolves around the sun and not around the earth.

Hence, option (3) is the correct answer.

DSSSB PGT Physics Mock Test - 2 - Question 16

The angle of contact for the liquid which wets the walls of the vessel is

Detailed Solution for DSSSB PGT Physics Mock Test - 2 - Question 16

When liquid molecules are attracted strongly to themselves and weakly to those of solids, it costs lots of energy to create liquid-solid surface and liquid then does not wet the solid.
For Example: Mercury molecules (which make an obtuse angle with glass) have a strong force of attraction between themselves and a weak force of attraction toward solids. Hence, they tend to form drops. 
On the other hand, water molecules make acute angles with glass. They have a weak force of attraction between themselves and a strong force of attraction toward solids. Hence, they tend to spread out.

DSSSB PGT Physics Mock Test - 2 - Question 17

The potential energy between two atoms in a diatomic molecule varies with x as   where a and b are positive constants. Find the equivalent spring constant for

the oscillation of one atom if the other atom is kept 

Detailed Solution for DSSSB PGT Physics Mock Test - 2 - Question 17

DSSSB PGT Physics Mock Test - 2 - Question 18

The distance travelled by a particle executing SHM in 10 s, if the time period is 3 s, is
(It is given that the body starts from A√3/3 from equilibrium position, moves is positive direction at t = 0)  

Detailed Solution for DSSSB PGT Physics Mock Test - 2 - Question 18

In 9s, the distance travelled = 4A × 3 = 12A 

Imagine, now it is at

 

 

DSSSB PGT Physics Mock Test - 2 - Question 19

The phenomenon of interference is based on the principle of _

Detailed Solution for DSSSB PGT Physics Mock Test - 2 - Question 19

The phenomenon of interference is based on the principle of superposition.

DSSSB PGT Physics Mock Test - 2 - Question 20

What is the number of electric field lines coming out from a 1C charge?

Detailed Solution for DSSSB PGT Physics Mock Test - 2 - Question 20

According to Gauss’s Law, the total number of electric field lines coming out of a charge q is =where εo is the absolute permittivity of air. Its value is 8.85 * 10-12. Therefore the number of lines coming out from a 1C charge = 1/8.85 * 10-12.

DSSSB PGT Physics Mock Test - 2 - Question 21

According to the standard convention, the electric potential at a point infinitely far from a charge is taken to be:

Detailed Solution for DSSSB PGT Physics Mock Test - 2 - Question 21

The standard convention states that the electric potential at a point infinitely far from a charge is considered to be:

  • Zero

This means that as you move further away from a charge, the potential energy associated with that charge diminishes to zero.

DSSSB PGT Physics Mock Test - 2 - Question 22

A particle of mass 1 Kg and charge 1/3 μC is projected towards a non conducting fixed spherical shell having the same charge uniformly distributed on its surface. The minimum intial velocity V0 of projection of particle required if the particle just grazes the shell is 

Detailed Solution for DSSSB PGT Physics Mock Test - 2 - Question 22

From conservation of angular momentum, 
mr0 = r/2 = mvr
⇒ v = v0/2
From conservation of energy,

DSSSB PGT Physics Mock Test - 2 - Question 23

The effective resistance between points P and Q of the electrical circuit shown in the figure is

Detailed Solution for DSSSB PGT Physics Mock Test - 2 - Question 23

The circuit is symmetrical about the axis POQ.
The circuit above the axis POQ represents balanced wheatstone bride. Hence the central resistance 2R is ineffective. Similarly in the lower part (below the axis POQ) the central resistance 2R is ineffective.

Therefore the equivalent circuit is drawn.

DSSSB PGT Physics Mock Test - 2 - Question 24

In the shown arrangement of the experiment of the meter bridge if AC corresponding to null deflection of galvanometer is x, what would be its value if the radius of the wire AB is doubled?

Detailed Solution for DSSSB PGT Physics Mock Test - 2 - Question 24

At null point

If radius of the wire is doubled, then the resistance of AC will change and also the resistance of CB will change. But since R1/Rdoes not change so, R3/R4
 should also not change at null point. Therefore the point C does not change.

DSSSB PGT Physics Mock Test - 2 - Question 25

Two particles A and B of masses mA and mB respectively and having the same charge are moving in a plane. A uniform magnetic field exists perpendicular to this plane. The speeds of the particles are vA and vB respectively and the trajectories are as shown in the figure. Then

Detailed Solution for DSSSB PGT Physics Mock Test - 2 - Question 25

KEY CONCEPT : When a charged particle is moving at right angles to the magnetic field then a force acts on it which behaves as a centripetal force and moves the particle in circular motion.

DSSSB PGT Physics Mock Test - 2 - Question 26

A long straight wire along the Z-axis carries a current I in the negative Z-direction. The magnetic vector field at a point having coordinates (x, y) in the Z = 0 plane is 

Detailed Solution for DSSSB PGT Physics Mock Test - 2 - Question 26

The wire carries a current I in the negative z-direction.
We have to consider the magnetic vector field

Magnetic field is perpendicular to OP.

DSSSB PGT Physics Mock Test - 2 - Question 27

Which one of the following, when suspended freely, slowly sets itself parallel to the direction of the magnetic field?

Detailed Solution for DSSSB PGT Physics Mock Test - 2 - Question 27

Paramagnetic materials are those when suspended freely inside the magnetic field, it slowly sets itself parallel to the direction of the magnetic field. When placed in a non-uniform magnetic field, it tends to move from weaker to a stronger magnetic field.

DSSSB PGT Physics Mock Test - 2 - Question 28

In the free oscillations of an LC circuit, the sum of energies stored in the capacitor and the inductor.

Detailed Solution for DSSSB PGT Physics Mock Test - 2 - Question 28

At any time, t
energy stored in capacitor, EC=q2/2C
Total energy stored in C and L at any time t
E=EC+EL
E=(q2/2C)+(LI2/2)
If q=q0sinωt
I=dq/dt=q0cosωtω=ωq0cosωt
Put in (i), E=[(q0sinωt)2/2C] + L(ωq0cosωt)2/2
E=(q02/2C) sin2ωt+(q02/2)cos2ωt.ω2L
But ω2=12/LC
∴E=(q02/2C) sin2ωt+(q02/2) (L/LC) cos2ωt
=q02/2C(sin2ωt+cos2ωt)
=q02/2C= constant in time.
 

DSSSB PGT Physics Mock Test - 2 - Question 29

Shape of the wave front of light diverging from a point source is

Detailed Solution for DSSSB PGT Physics Mock Test - 2 - Question 29

The shape of the wave front in case of a light diverging from a point source is spherical and is shown in the given figure. The shape of the wavefront in case of a light emerging out of a convex lens when a point source is placed at its focus is a parallel grid.

DSSSB PGT Physics Mock Test - 2 - Question 30

A car of mass 800 kg moves on a circular track of radius 40 m. If the coefficient of friction is 0.5, then the maximum velocity with which the car can move is

Detailed Solution for DSSSB PGT Physics Mock Test - 2 - Question 30
When a car goes round a curved road, it requires some centripetal force. While rounding the curve, the wheels of the car have a tendency to leave the curved path and regain the straight line path. Force of friction between the wheels and the road opposes this tendency of the wheels. This force (of friction) therefore acts, towards the centre of the circular track and provides the necessary centripetal force.

Hence, the maximum velocity with which a vehicle can go round a level curve, without skidding is Here, r = 40 m

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