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VITEEE PCBE Mock Test - 7 - JEE MCQ


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30 Questions MCQ Test VITEEE: Subject Wise and Full Length MOCK Tests - VITEEE PCBE Mock Test - 7

VITEEE PCBE Mock Test - 7 for JEE 2025 is part of VITEEE: Subject Wise and Full Length MOCK Tests preparation. The VITEEE PCBE Mock Test - 7 questions and answers have been prepared according to the JEE exam syllabus.The VITEEE PCBE Mock Test - 7 MCQs are made for JEE 2025 Exam. Find important definitions, questions, notes, meanings, examples, exercises, MCQs and online tests for VITEEE PCBE Mock Test - 7 below.
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VITEEE PCBE Mock Test - 7 - Question 1

Which of the following correctly describes the role of viroids?

Detailed Solution for VITEEE PCBE Mock Test - 7 - Question 1

Viroids are unique infectious agents made up solely of a short strand of RNA, without a protein coat, known for causing diseases in plants such as potato spindle tuber disease. This makes Option C correct. Option A incorrectly describes prions, not viroids; Option B is false as viroids are smaller than viruses and lack DNA; Option D describes lichens, not viroids.

VITEEE PCBE Mock Test - 7 - Question 2

What type of blood circulatory system do cockroaches have?

Detailed Solution for VITEEE PCBE Mock Test - 7 - Question 2

Cockroaches, like many other insects, possess an open circulatory system. This system is characterized by a limited network of blood vessels and a heart that pumps the hemolymph (blood) into the body cavity, where it directly bathes the organs. There is no distinction between blood and interstitial fluid in this type of system, unlike in closed circulatory systems.

VITEEE PCBE Mock Test - 7 - Question 3

What is the defining characteristic of renal calculi?

Detailed Solution for VITEEE PCBE Mock Test - 7 - Question 3

Renal calculi are characterized by the presence of an insoluble mass of crystallized salts within the kidney. These formations can vary in size and composition, often leading to symptoms such as severe pain, hematuria (blood in urine), and urinary obstruction. It is crucial to manage these calculi through dietary changes, hydration, and medical interventions to prevent complications like kidney damage or recurrent stone formation.

Topic in NCERT: Renal calculi

Line in NCERT: "Renal calculi: Stone or insoluble mass of crystallised salts (oxalates, etc.) formed within the kidney."

VITEEE PCBE Mock Test - 7 - Question 4

Read the following four statements carefully.
(i) Asthma is a difficulty in breathing causing wheezing due to inflammation of bronchi and bronchioles.
(ii) The part of the respiratory system starting with the external nostrils up to the terminal bronchioles constitutes the respiratory or exchange part of the respiratory system.
(iii) During swallowing epiglottis can be covered by a thin elastic cartilaginous ilap calied glottis to prevent the entry of food into the larynx.
(iw) Binding of oxygen with haemoglobin is primarily related to partial pressure of O2. Which of the above two statements are correct?

Detailed Solution for VITEEE PCBE Mock Test - 7 - Question 4

Both statements (i) and (iv) are correct. Asthma is a difficulty in breathing caused by inflammation of the bronchi and bronchioles, and the binding of oxygen to hemoglobin is primarily related to the partial pressure of O2.

Statements (ii) and (iii) are not correct. The respiratory system starts at the external nostrils and extends to the alveoli, not the terminal bronchioles. The epiglottis is a flap of cartilage that covers the glottis to prevent the entry of food into the larynx during swallowing, not the other way around.

VITEEE PCBE Mock Test - 7 - Question 5

Which hormone is primarily responsible for cell elongation in plants?

Detailed Solution for VITEEE PCBE Mock Test - 7 - Question 5

Auxin is a plant hormone known for its role in promoting cell elongation, especially in the stem. It regulates various aspects of growth and development by facilitating the stretching of cell walls, allowing cells to expand.

VITEEE PCBE Mock Test - 7 - Question 6

What is the primary site for the exchange of gases in the human body?

Detailed Solution for VITEEE PCBE Mock Test - 7 - Question 6

Solution: The alveoli are the primary sites for the exchange of gases. They are tiny, balloon-like structures in the lungs where oxygen is absorbed into the blood and carbon dioxide is released from the blood. This process is facilitated by the large surface area and thin walls of the alveoli, making them perfectly suited for gas exchange.

VITEEE PCBE Mock Test - 7 - Question 7

The course of blood from the heart to the lungs and back to the heart is called

Detailed Solution for VITEEE PCBE Mock Test - 7 - Question 7

The blood circulation from heart to lungs and back to heart is pulmonary circulation and the circulation between heart to tissue and back to heart is systematic circulation and both are included in double circulation.

VITEEE PCBE Mock Test - 7 - Question 8

The notation p and q of the Hardy Weinberg equation represent ________ of a diploid organism.

Detailed Solution for VITEEE PCBE Mock Test - 7 - Question 8

Individual frequencies can be represented as p and q. But for a diploid organism, p and q explain the frequency of allele A and allele a. p2 represents AA whereas q2 represent aa.

VITEEE PCBE Mock Test - 7 - Question 9

What can you infer about the structures shown in figure?

Detailed Solution for VITEEE PCBE Mock Test - 7 - Question 9

Given figures represent the forelimbs of different vertebrates, which possess the same basic structural plan, i.e., in each case, the forelimb consists of humerus, radio-ulna, carpals, metacarpals and digits. Thus, the skeletal parts of these forelimbs are similar in structure and arrangement, but have different shapes and functions. It depicts the example of homologous structures.

VITEEE PCBE Mock Test - 7 - Question 10

Read statements (i)-(iv). Which of the following statements are correct?
(i) Restriction enzymes belong to a larger class of enzymes called nucleases.
(ii) Restriction enzymes are used to cut DNA at specific sites.
(iii) Downstream processing is one of the steps of rDNA technology.
(iv) Disarmed pathogen vectors are also used in the transfer of rDNA into the host.

Detailed Solution for VITEEE PCBE Mock Test - 7 - Question 10

Lines in NCERT: 1. Restriction enzymes belong to a larger class of enzymes called nucleases.
2. The cutting of DNA at specific locations became possible with the discovery of the so-called  ‘molecular scissors’– restriction enzymes.
3. Downstream processing is the last process in recombinant DNA technology(6th). After completion of the biosynthetic stage, the product has to be subjected through a series of processes before it is ready for marketing as a finished product.
4. And the last method uses ‘disarmed pathogen’ vectors, which when allowed to infect the cell, transfer the recombinant DNA into the host.

VITEEE PCBE Mock Test - 7 - Question 11

Assertion (A): Competitive inhibitors bind to the active site of an enzyme, preventing substrate binding.

Reason (R): Competitive inhibition can be overcome by increasing the concentration of the substrate.

Detailed Solution for VITEEE PCBE Mock Test - 7 - Question 11

- The Assertion is correct because competitive inhibitors indeed bind to the active site of an enzyme, which prevents the substrate from binding.

- The Reason is also correct as increasing the substrate concentration can outcompete the inhibitor for the active site, thereby restoring enzyme activity.

- Additionally, the Reason effectively explains the Assertion as it describes how competitive inhibition can be mitigated, confirming that both statements are true and that the Reason is the correct explanation for the Assertion.

VITEEE PCBE Mock Test - 7 - Question 12

The given graph shows the change in DNA content during various phases (A to D) in a typical mitotic cell cycle. Identify the phases and select the correct option.

Detailed Solution for VITEEE PCBE Mock Test - 7 - Question 12

During G1 phase, DNA content is 2C.S phase is marked by replication of DNA and the amount of DNA per cell is doubled. During G2 phase, synthesis of RNA and proteins takes place. During mitosis, DNA content gets equally distributed among two daughter cells.

Topic in NCERT: CELL CYCLE AND CELL DIVISION

Line in NCERT: "The interphase is divided into three further phases: G1 phase (Gap 1), S phase (Synthesis), G2 phase (Gap 2)."

VITEEE PCBE Mock Test - 7 - Question 13
The electron volt is a unit of
Detailed Solution for VITEEE PCBE Mock Test - 7 - Question 13
The electron volt (symbol eV; also written as 'electronvolt') is a unit of energy equal to approximately 1.602 × 10−19 joules (SI unit J).
By definition, it is the amount of energy gained by the charge of a single electron moved across an electric potential difference of one volt.
VITEEE PCBE Mock Test - 7 - Question 14
An inductor is connected to a battery through a switch. Induced e.m.f. is e1 when the switch is pressed, and is e2 when the switch is opened. In this case,
Detailed Solution for VITEEE PCBE Mock Test - 7 - Question 14
When we close the switch, the current takes some time to build in the circuit because the inductance of the inductor opposes the build up of the current in accordance with the Lenz's law. When we open the switch, rate of decrease of current is much more because inductance of the inductor tries to increase the decreasing magnetic flux. So, the e.m.f. induced when the switch is opened is more than the e.m.f. induced when the switch is closed.
VITEEE PCBE Mock Test - 7 - Question 15

The refractive index of glass with respect to a medium is 4/3. If the difference between the velocities of light in medium and in glass is 6.25 x 107 m/s, then what is the velocity of light in the medium?

Detailed Solution for VITEEE PCBE Mock Test - 7 - Question 15

When light goes from one medium to another, the frequency of light, and phase of light do not change.
However, the velocity of light and wavelength of light change.
So, velocity of light in glass
vg = or vm - vg = vm -
∴ 6.25 × 107 = vm
= 2.5 × 108 m/s

VITEEE PCBE Mock Test - 7 - Question 16

The magnetic moment (µ) of a revolving electron around the nucleus varies with principal quantum number n as

Detailed Solution for VITEEE PCBE Mock Test - 7 - Question 16

Velocity of the electron orbiting around the nucleus
v ∝ 1/n _____ 1
and
Radius of the orbit
r ∝ n2 ____ 2
Magnetic moment (μ) = (mvr)/2 (m is mass of the electron which is constant) ........... (3)
Therefore,
From 1, 2 and 3 we have
μ ∝ n

VITEEE PCBE Mock Test - 7 - Question 17

In electromagnetic wave of frequency v = 3.0 MHz passes from vacuum into a dielectric medium with relative permittivity εr = 4.0 Then

Detailed Solution for VITEEE PCBE Mock Test - 7 - Question 17

Velocity of electromagnetic wave in a medium with relative permittivity εr = 4 ,

Velocity of wave,  where ε0, μ0 are electrical permittivity and magnetic permeability of vacuum.

Frequency (f) is the fundamental property of wave and it doesn't change unless we change the waves itself, hence remains constant hence,

λf = c, where λ is the wavelength of the wave,

Also, When a wave propagates from one medium to the other, then the frequency remains the same. So,


∴ Wavelength is halved and frequency remains unchanged.

VITEEE PCBE Mock Test - 7 - Question 18

If t(1 + x²) = x, and x² + t² = y, then at x = 2, t = 2, the value of dy/dx is:

Detailed Solution for VITEEE PCBE Mock Test - 7 - Question 18

Given:

Differentiate w.r.t. x on both sides,

.

Using quotient rule in differentiation i.e. 

 

Also given, x2 + t2 = y

Differentiate w.r.t. x on both sides,

Put the value of tand dt/dx from equations (i) and (ii),

Now put x = 2. We get

VITEEE PCBE Mock Test - 7 - Question 19

A man who wears glasses of power 3 diopters must hold a newspaper at least 25 cm away to see the print clearly. How far away would the newspaper have to be if he took off the glasses and still wanted clear vision?

Detailed Solution for VITEEE PCBE Mock Test - 7 - Question 19

The virtual image formed by the lens is at the naked eye's true near point.
∴ P = 25 cm


∴ 1/q = – 0.01
∴ q = 100 cm
∴ When the man is not wearing the glasses he should hold the newspaper 1m away for clear vision.
The answer is(A)

VITEEE PCBE Mock Test - 7 - Question 20

The conversion of RCOOH to RCH2OH can be obtained by

Detailed Solution for VITEEE PCBE Mock Test - 7 - Question 20

The conversion of RCOOH to RCH2OH can be obtained by lithium aluminium hydride.
NaBH4 does not reduce carboxylic acids.
Red P/HI would reduce it to the hydrocarbon stage.
Zn-Hg/conc. HCl: Clemmensen reduction is done for conversion of aldehydes to hydrocarbons

VITEEE PCBE Mock Test - 7 - Question 21

Thermal decomposition of N2O5 occurs as per the equation below:
2N2O5 → 4NO2 + O2
The correct statement is

Detailed Solution for VITEEE PCBE Mock Test - 7 - Question 21

2N2O5  4 NO2 + O2

Production rate of O2 =
Production rate of NO2 =
Disappearance rate of N2O5 =

[Rate of disappearance of N2O5 = Twice the production rate of O2]

VITEEE PCBE Mock Test - 7 - Question 22

Which one of the following aqueous solutions will exhibit the highest boiling point?

Detailed Solution for VITEEE PCBE Mock Test - 7 - Question 22

Boiling point = T0 (Solvent) + ΔTb (Elevation in b.p.)
ΔTb = miKb
where, m is the molality (≈ Molarity M)
i, the van’t Hoff factor = [1 + (y – 1)x]
Kb, molal elevation constant.
Thus ΔTb ∝ i
Assume 100% ionisation
(a) mi (Na2 SO4) = 0.01[1 + (y – 1)x] = 0.03
(b) mi (KNO3) = 0.01 × 2 = 0.02
(c) mi (urea) = 0.015
(d) mi (glucose) = 0.015

VITEEE PCBE Mock Test - 7 - Question 23

Which of the following has the strongest base?

Detailed Solution for VITEEE PCBE Mock Test - 7 - Question 23

These are all Lewis bases as N-atom in each of them has tendency to donate an electron pair. Piperidine (c) is the strongest base among these. In pyrrole (b), the lone pair of electrons on N-atom is involved in delocalisation of π electrons (aromatic sextet). Hence, it has the least tendency to donate an electron pair. Aniline (d) and pyridine (a) are also weakly basic due to resonance. On the other hand, piperidine has no such delocalisation and it is a secondary amine. Hence, it is highly basic.

VITEEE PCBE Mock Test - 7 - Question 24
The characteristic that does not contribute to catalytic activities of transition elements is
Detailed Solution for VITEEE PCBE Mock Test - 7 - Question 24
The tendency of transition elements to exhibit variable oxidation states enables them to form intermediates with lower ionisation energies.
VITEEE PCBE Mock Test - 7 - Question 25

Out of the following, the aromatic compound(s) is/are:

Detailed Solution for VITEEE PCBE Mock Test - 7 - Question 25

Both (B) and (C) have 6π electrons and obey Huckel's rule of (4n + 2)π electrons. Hence, they are aromatic in nature. This character is attributed to the structure because -OH group present in the side chain is not directly attached to the ring and hence, the lone pair on the oxygen atom is not in conjugation with the π electrons of the benzene ring.

VITEEE PCBE Mock Test - 7 - Question 26

When a substance A reacts with water, it produces a combustible gas B and a solution of a substance C in water. When another substance D reacts with this solution of C, it also produces the same gas B, even on reaction with dilute sulphuric acid at room temperature. A imparts a deep golden yellow color to a smokeless flame of a Bunsen burner.A, B, C, and D respectively are:

Detailed Solution for VITEEE PCBE Mock Test - 7 - Question 26

Na + H2O → NaOH + 1/2H2
Zn + 2NaOH → Na2ZnO2 + H2
Na imparts a Golden yellow colour to the flame

VITEEE PCBE Mock Test - 7 - Question 27

Directions: In the following question, alternatives are given for the idiom/phrase underlined in the sentence. Choose the alternative which best expresses the meaning of the idiom/phrase.

Thousands put on a daily fight to keep the wolf from the door.

Detailed Solution for VITEEE PCBE Mock Test - 7 - Question 27

'Keep the wolf from the door' means 'have enough money to avert hunger or starvation' 
'Starvation' is a noun which means 'suffering or death caused by lack of food.'
For example: I work part-time to pay the mortgage and keep the wolf from the door
Hence, this is the correct option. 

VITEEE PCBE Mock Test - 7 - Question 28

Pablo's father gave up painting because he 

Detailed Solution for VITEEE PCBE Mock Test - 7 - Question 28

The line of passage, 'He returned to find that Pablo had completed the picture and it was so amazingly beautiful and lifelike that he gave his son his palette and brushes and never painted again' clearly depicts that Pablo had become an amazing artist so, his father gave up painting.
Hence, option C is the right answer.

VITEEE PCBE Mock Test - 7 - Question 29

Choose the word which is most nearly the OPPOSITE in meaning as the word printed in bold as used in the passage.
Addressed

Detailed Solution for VITEEE PCBE Mock Test - 7 - Question 29

Disregarded means pay no attention to or  ignore.
Whereas Addressed is an adjective which means  bearing the name and address of the intended recipient.
Addressed : Disregarded (should be the exact antonym)
Therefore option A is correct option.

VITEEE PCBE Mock Test - 7 - Question 30

How many such pairs of letters are there in the word SEARCHES, each of which has as many letters between them in the word as in the English alphabet?

Detailed Solution for VITEEE PCBE Mock Test - 7 - Question 30

In the word, A and C have one letter between them , in alphabetical order A and C have only letter B between them
C and E have one letter between them , in alphabetical order C and E have only letter D between them
A and E have three letter between them , in alphabetical order A and E have three letters B, C and D between them
Therefore, (A,C) ; (C,E) and (A,E) are three pairs which satisfy the given condition.
Option D is correct

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