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Bhaskar had two sons Uday and Surya whose ages are 12 and 14 Years respectively. He deposited equal money on each of them in two different Banks which offered 6% , 8% Simple Interest to Uday and Surya respectively. Bhaskar plan is such that at certain age both of their amounts will become equal. Then at what age their amounts will be equal?
  • a)
    20
  • b)
    21
  • c)
    24
  • d)
    27
  • e)
    Cannot be determined
Correct answer is option 'A'. Can you explain this answer?

P×6×{t+2}/100 = p×8×t/100
6(t+2) = 8t
2t= 12
t= 6 years
so age of Surya= 14+t= 14 +6= 20 years
age of Uday= 12 + (t+2)= 12 + 6+2 = 20 years
bcz surya is 2 years are older than Uday.
That's why equal S.I. gained by both takes 6 years and 8 years respectively.
so , at 20 years age both will get equal amount.

Q. 
In HCL, if the ratio of the number of students Attended to the number of candidates qualified is 8:5, and the number of Males qualified was 88704 then number of Females qualified is?
  • a)
    81168
  • b)
    81568
  • c)
    82068
  • d)
    82368
  • e)
    Cannot be determined
Correct answer is option 'D'. Can you explain this answer?

Aisha Gupta answered
If the ratio of number of students Attended to number of candidates qualified is 8:5 then percentage of candidates qualified out of attended is 60%
297*96*6*(M/M+13) = 88704
M = 14
Then Females = 297*96*6*13/27 = 82368

224,?,444,1329,5312,26555
  • a)
    223
  • b)
    224
  • c)
    324
  • d)
    412
  • e)
    444
Correct answer is option 'A'. Can you explain this answer?

Ravi Singh answered
224*1-1 = 223
223*2 -2 = 444
444*3 – 3 = 1329
1329*4 – 4 = 5312
5312*5 – 5 = 26555

Shiva is running on a road at the rate of 10 Km/hr. In the same direction a Bus going at a speed of 130 Km/hr passed him. He could see the Bus only for 30 Seconds. Then up to what distance he could see the Bus?
  • a)
    1 Km
  • b)
    2 Km
  • c)
    3 Km
  • d)
    4 Km
  • e)
    Cannot be determined
Correct answer is option 'A'. Can you explain this answer?

Sagar Sharma answered
Distance Formula
To solve this problem, we need to use the distance formula. The distance formula is given by:

Distance = Speed x Time

Given Information
From the given information, we know the following:

Shiva's speed = 10 km/hr
Bus's speed = 130 km/hr
Time = 30 seconds

Calculating the Distance
To calculate the distance, we need to convert the time from seconds to hours. Since there are 60 seconds in a minute and 60 minutes in an hour, we divide the time by 3600 (60 x 60) to convert it to hours.

Time = 30 seconds ÷ 3600 = 0.00833 hours

Next, we use the distance formula to calculate the distance Shiva could see the bus:

Distance = Speed x Time
Distance = 10 km/hr x 0.00833 hours
Distance = 0.0833 km

Answer
Therefore, Shiva could see the bus up to a distance of 0.0833 km, which is approximately equal to 1 km.

Explanation
When Shiva is running at a speed of 10 km/hr, he can see the bus for a certain amount of time. In this case, the time is given as 30 seconds. To calculate the distance that Shiva could see the bus, we need to use the distance formula. The distance formula states that the distance is equal to the speed multiplied by the time. By substituting the given values into the formula, we can find the distance. After converting the time from seconds to hours, we multiply it by Shiva's speed to get the distance. In this case, the distance is approximately equal to 0.0833 km, which is rounded to 1 km. Therefore, the correct answer is option A - 1 km.

A lift in an Apartment which has 6 floors stops on every floor. If 4 people enter the lift when it was in ground level(ground is not a floor). What is the probability that all will get out on different floors?
  • a)
    6!/2!*64
  • b)
    4!/2!*64
  • c)
    6!/4!*64
  • d)
    4!/6!
  • e)
    None
Correct answer is option 'E'. Can you explain this answer?

Sagar Sharma answered
To find the probability that all four people will get out on different floors, we need to consider the number of possible outcomes and the number of favorable outcomes.

Number of possible outcomes:
When each person gets off on a different floor, there are 6 possible choices for the first person, 5 choices for the second person, 4 choices for the third person, and 3 choices for the fourth person. Therefore, the number of possible outcomes is 6 * 5 * 4 * 3 = 360.

Number of favorable outcomes:
Since there are 6 floors and each person needs to get off on a different floor, the first person has 6 choices, the second person has 5 choices (as one floor is already occupied by the first person), the third person has 4 choices, and the fourth person has 3 choices. Therefore, the number of favorable outcomes is 6 * 5 * 4 * 3 = 360.

Probability:
The probability of an event occurring is given by the ratio of the number of favorable outcomes to the number of possible outcomes. In this case, the number of favorable outcomes is equal to the number of possible outcomes. Hence, the probability is 360/360 = 1.

Therefore, the correct answer is option E) None, as the probability of all four people getting out on different floors is 1.

Q. 
What is the average profit made Shop A, B and C on Mouse?
  • a)
    345
  • b)
    335
  • c)
    325
  • d)
    315
  • e)
    None
Correct answer is option 'C'. Can you explain this answer?

Vishal Musmade answered
If we can do total profit =(13+9+17)/3
so it is 13 we multiple this with cost we will get ans
(13/100)*2500=325

A building contractor takes contract to do a work in 30 days by 40 men. In the first 10 days 10 men were absent. In the second 10 days all men were present. Now how many more men he need to employ so that work is finished in time?
  • a)
    10
  • b)
    20
  • c)
    30
  • d)
    40
  • e)
    None
Correct answer is option 'A'. Can you explain this answer?

Sagar Sharma answered
Understanding the Problem
A contractor has to complete a project in 30 days using 40 men. The work is divided into three segments over these 30 days.
Work Distribution
- Total Work: The total work can be calculated as "man-days" which is 40 men * 30 days = 1200 man-days.
Work Done in the First 10 Days
- Men Present: During the first 10 days, 10 men were absent, leaving 30 men available.
- Work Done:
- Work done in 10 days = 30 men * 10 days = 300 man-days.
Work Done in the Second 10 Days
- Men Present: All 40 men were present in the next 10 days.
- Work Done:
- Work done in the second 10 days = 40 men * 10 days = 400 man-days.
Total Work Completed
- Total Work After 20 Days:
- Total work done in 20 days = 300 man-days + 400 man-days = 700 man-days.
Remaining Work
- Remaining Work:
- Remaining work = Total work - Work done = 1200 man-days - 700 man-days = 500 man-days.
Time Remaining
- Days Left:
- Days remaining = 30 days - 20 days = 10 days.
Calculating Additional Men Needed
- Men Needed:
- To complete 500 man-days in 10 days, the required number of men = Remaining work / Days remaining = 500 man-days / 10 days = 50 men.
- Additional Men Required:
- Since there are already 40 men, additional men needed = 50 men - 40 men = 10 men.
Conclusion
The contractor needs to employ 10 more men to finish the work on time. Thus, the correct answer is option 'A'.

I. 2X² – 152X + 56 = 0
II. 2Y² – 172Y + 72= 0
  • a)
    X > Y
  • b)
    X < Y
  • c)
    X ≥ Y
  • d)
    X ≤ Y
  • e)
    X = Y or relationship cannot be established
Correct answer is option 'D'. Can you explain this answer?

Sagar Sharma answered
Understanding the Equations
We have two quadratic equations to analyze:
- I. 2X² – 15√2X + 56 = 0
- II. 2Y² – 17√2Y + 72 = 0
Step 1: Solving for X
To find the roots (X values) of equation I:
- The coefficients are: a = 2, b = -15√2, c = 56.
- Using the quadratic formula, X = [ -b ± √(b² - 4ac) ] / 2a.
Calculating the discriminant (b² - 4ac):
- b² = (-15√2)² = 450
- 4ac = 4 * 2 * 56 = 448
- Discriminant = 450 - 448 = 2 (positive, hence two real roots)
Now, compute the roots:
- X1 = [15√2 + √2] / 4 = (15 + 1)√2 / 4 = 16√2 / 4 = 4√2
- X2 = [15√2 - √2] / 4 = (15 - 1)√2 / 4 = 14√2 / 4 = 3.5√2
Step 2: Solving for Y
Now for equation II:
- The coefficients are: a = 2, b = -17√2, c = 72.
- Using the quadratic formula again.
Calculating the discriminant:
- b² = (-17√2)² = 578
- 4ac = 4 * 2 * 72 = 576
- Discriminant = 578 - 576 = 2 (positive, two real roots)
Now, compute the roots:
- Y1 = [17√2 + √2] / 4 = (17 + 1)√2 / 4 = 18√2 / 4 = 4.5√2
- Y2 = [17√2 - √2] / 4 = (17 - 1)√2 / 4 = 16√2 / 4 = 4√2
Comparing X and Y
From the calculations:
- X values: 4√2 and 3.5√2
- Y values: 4.5√2 and 4√2
Conclusion
- The maximum value of X (4√2) is equal to the minimum value of Y (4√2).
- Since the values of X can be less than or equal to Y, the correct answer is option 'D': X ≤ Y.

I. 3X + 4Y = 64
II. 2X + 3Y = 56
  • a)
    X > Y
  • b)
    X < Y
  • c)
    X ≥ Y
  • d)
    X ≤ Y
  • e)
    X = Y or relationship cannot be established
Correct answer is option 'B'. Can you explain this answer?

Sagar Sharma answered
Given Equations:
I. 3X + 4Y = 64
II. 2X + 3Y = 56

Explanation:

Step 1: Solving the Equations
To find the relationship between X and Y, we need to solve the given equations simultaneously.
Multiplying Equation I by 2 and Equation II by 3:
6X + 8Y = 128
6X + 9Y = 168
Subtracting Equation I from Equation II:
Y = 40
Substituting Y = 40 in Equation I:
3X + 4(40) = 64
3X + 160 = 64
3X = -96
X = -32

Step 2: Comparing X and Y
X = -32 and Y = 40
Since X is less than Y (X < y),="" the="" correct="" answer="" is="" option="" b)="" x="" />< />
Therefore, the relationship between X and Y is that X is less than Y in this scenario.

Parthiv’s wife age is 24 and his Son age is 12 as on today. On same day Partiv invented a Time Machine through which he travelled to ancient time. He stayed in ancient time for 6 Years then he returned back. But by Surprise, there is no change in Parthiv’s age after his return. If the difference between the average age of the family before and after is only 4 then Parthiv’s age is?
  • a)
    33
  • b)
    39
  • c)
    40
  • d)
    41
  • e)
    Cannot be determined
Correct answer is option 'E'. Can you explain this answer?

Sagar Sharma answered
Understanding the Family's Age Before Time Travel
- Parthiv's wife's age: 24 years
- Son's age: 12 years
- Parthiv's age: Let’s denote it as P.
Calculating the Average Age Before Time Travel
- Total age before time travel = P + 24 + 12 = P + 36
- Number of family members = 3
- Average age before time travel = (P + 36) / 3
Time Travel Duration
- Time spent in ancient time: 6 years
- After returning, Parthiv's age remains P, while his wife and son age 6 years:
- Wife's new age = 24 + 6 = 30
- Son's new age = 12 + 6 = 18
Calculating the Average Age After Time Travel
- Total age after time travel = P + 30 + 18 = P + 48
- Average age after time travel = (P + 48) / 3
Difference in Average Ages
- Given that the difference in averages is 4:
- [(P + 48) / 3] - [(P + 36) / 3] = 4
- Simplifying gives:
- (P + 48 - P - 36) / 3 = 4
- 12 / 3 = 4 (which holds true)
Conclusion: Age of Parthiv
The equation does not provide a specific value for P, meaning it could be any value that satisfies the overall condition of age difference. Thus, the exact age of Parthiv cannot be determined based solely on the information provided, leading to the answer being option 'E' (Cannot be determined).

I.2X² – (4+14)X +56 = 0
II.10Y² – (18+514)Y + 914 =0
  • a)
    X > Y
  • b)
    X <Y
  • c)
    X ≥ Y
  • d)
    X ≤ Y
  • e)
    X = Y or relationship cannot be established
Correct answer is option 'C'. Can you explain this answer?

Sagar Sharma answered
Understanding the Equations
The given equations are quadratic equations in X and Y. We need to analyze each equation to determine the relationship between their roots.
Equation I: 2X² - (4 + √14)X + √56 = 0
- For this quadratic equation in X, we can find the roots using the quadratic formula:
X = [-(b) ± √(b² - 4ac)] / (2a)
Here, a = 2, b = -(4 + √14), and c = √56.
- The roots' relationship will depend on the discriminant (D):
D = b² - 4ac.
If D > 0, there are two distinct real roots; if D = 0, one real root; and if D < 0,="" no="" real="" />
Equation II: 10Y² - (18 + 5√14)Y + 9√14 = 0
- Similarly, for this quadratic in Y, use the quadratic formula:
Y = [-(b) ± √(b² - 4ac)] / (2a)
Here, a = 10, b = -(18 + 5√14), and c = 9√14.
- Again, compute the discriminant (D):
D = b² - 4ac, with the same implications for the roots.
Comparing the Roots
- Both equations represent parabolas, and their roots can be numerical values based on the discriminants.
- If we compute the discriminants and find them to be equal, or if they yield roots that are numerically the same, we can establish that X = Y.
- If the discriminants are positive but yield different values, we would need to compare the roots directly to ascertain if X > Y or X < />
Conclusion
Given that the correct answer is 'C', it implies that after analyzing the roots from both equations, they can be equal or cannot be distinctly separated. Thus, X can be greater than or equal to Y depending on the specific values computed from the equations.

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