All Exams  >   NEET  >   Chemistry CUET UG Mock Test Series 2026  >   All Questions

All questions of Electrochemistry for NEET Exam

Chemical used in salt bridge is
a. KOH
b. KCI
c. KNO2
d. KBr
Correct answer is option 'B'. Can you explain this answer?

Anand Saha answered
KCl is used as salt bridge because it provides positive K+ ions and negative Cl- ions as the salt bridge needs to maintain the neutrality in the system by providing enough negative ions equal to the positive ions during oxidation.

The reduction potential of an element A is -2.71V.What can be concluded from this?
  • a)
    A will be a good oxidising agent
  • b)
    A will accept electrons easily
  • c)
    A will undergo reduction easily
  • d)
    A will undergo oxidation easily
Correct answer is 'D'. Can you explain this answer?

Reduction Potential of Element A

The reduction potential of an element A is -2.71V. This means that the element A has a strong tendency to undergo oxidation and lose electrons. The more negative the reduction potential value, the easier it is for the element to undergo oxidation and lose electrons.

Explanation of Options

a) A will be a good oxidising agent - This statement is incorrect. A good oxidizing agent is one that accepts electrons from other species and undergoes reduction. But, since the reduction potential of element A is negative, it indicates that the element A is likely to undergo oxidation and lose electrons, so it is not a good oxidizing agent.

b) A will accept electrons easily - This statement is incorrect. The reduction potential value is negative, which means that the element A has a strong tendency to lose electrons and undergo oxidation, rather than accepting electrons and undergoing reduction.

c) A will undergo reduction easily - This statement is incorrect. The reduction potential value is negative, which means that the element A has a strong tendency to undergo oxidation and lose electrons, rather than undergoing reduction and gaining electrons.

d) A will undergo oxidation easily - This statement is correct. The reduction potential value of element A is negative, which means that the element A has a strong tendency to undergo oxidation and lose electrons. The more negative the reduction potential value, the easier it is for the element to undergo oxidation and lose electrons. Therefore, element A will undergo oxidation easily.

Conclusion

The correct answer is option 'D'. The reduction potential value of an element indicates its tendency to undergo oxidation or reduction. A negative reduction potential value indicates a strong tendency to undergo oxidation and lose electrons, while a positive reduction potential value indicates a strong tendency to undergo reduction and gain electrons.

Hydrogen gas is not liberated when the following metal is added to dil. HCl.
  • a)
    Mg
  • b)
    Sn
  • c)
    Ag
  • d)
    Zn
Correct answer is option 'C'. Can you explain this answer?

Nikita Singh answered
The metals, present below hydrogen in the electrochemical series, cannot liberate hydrogen from the dilute acids.
Among the given metals only Ag is present below hydrogen in electrochemical series, so it does not evolve hydrogen with dil HCl.
Ag−IdilHCl ⟶ No reaction

Temperature for the measurement of standard electrode potential is
  • a)
    298K
  • b)
    300K
  • c)
    30?C​
  • d)
    310K
Correct answer is option 'A'. Can you explain this answer?

Anaya Patel answered
The standard electrode potentials are customarily determined at solute concentrations of 1 Molar, gas pressures of 1 atmosphere, and a standard temperature which is usually 25°C i.e, 298 K.

Calculate the standard cell potentials of galvanic cell, ∆rG and equilibrium constant of the reactions if the reaction is
  • a)
    0.01V, – 2.800 kJ mol–1, 3.2
  • b)
    0.03V, – 2.895 kJ mol–1, 3.2
  • c)
    0.02V, – 2.850 kJ mol–1, 3.2
  • d)
    0.04V, – 2.955 kJ mol–1, 3.2
Correct answer is option 'B'. Can you explain this answer?

The standard emf of a galvanic cell involving 3 moles of electrons in its redox reaction is 0.59V.
cell​ = 0.59V
n=3
The equilibrium constant for the reaction of the cell is given by the expression: ln K = RT nFEºcell
ln K = 8.314 × 298 × 3 × 96500 × 0.59 = 68.9
K≈1030
The equilibrium constant for the reaction of the cell is 1030.

The free energy change for the following cell reaction is given as :
2Au3+ (aq) + 3Cu (s) → 2Au (s) + 3Cu2+ (aq)
  • a)
    6 FE°cell
  • b)
    3 FE°cell
  • c)
    -2 FE°cell
  • d)
    -6 FE°cell
Correct answer is option 'D'. Can you explain this answer?

Preeti Iyer answered
The correct answer is Option D.
EO = EOCa2+/ Ca  -  EOAu2+/ Au
        = -2.87 - (1.50)
     = -2.87 - 1.50
     = -4.37 V
rGO = -nFEO
           = -6 FEO

Select the correct statement(s).
  • a)
    (molar conductance at infinite dilution) of strong electrolytes as well as weak electrolytes can be obtained by Kohlrausch’s law.
  • b)
     of strong as well as weak electrolytes can be obtained by extrapolation of graph between 
  • c)
    can be obtained by known value of 
  • d)
Correct answer is option 'A,C,D'. Can you explain this answer?

Anaya Patel answered


For strong electrolyte, variation in graph is uniform, hence can be extrapolated to
In case of weak electrolyte, variation of is rapid in lower concentration range (higher dilution), hence graph is not uniform and cannot be obtained by extrapolation to
Thus, (b) is incorrect.


Thus, correct based on Kohlrausch’s law.

Thus, it is also correct based on Kohlrausch's law.  

 Consider the following reaction which of the following statement is true for this cell reaction.
(Zn + Cu2+ → Zn2+ + Cu)
  • a)
    Zn2+ ions are oxidized to Zn
  • b)
    Zn is oxidized to Zn2+ ions
  • c)
    Zn is reduced to Zn2+ ions
  • d)
    Cu2+ ions are oxidized to Cu
    •  
Correct answer is option 'B'. Can you explain this answer?

Geetika Shah answered
  • For the reaction Zn + Cu2+ → Zn2+ + Cu, Zn is oxidized to Zn2+ while Cu2+ is reduced to Cu
  • In a redox reaction, the reactant that loses electrons (is oxidized) causes a reduction and is called a reducing agent. In the example above, zinc metal is the reducing agent; it loses two electrons (is oxidized) and becomes Zn2+ ion.

The reduction potential of an element A is -2.71V.What can be concluded from this?
  • a)
    A will be a good oxidising agent
  • b)
    A will accept electrons easily
  • c)
    A will undergo reduction easily
  • d)
    A will undergo oxidation easily
Correct answer is option 'D'. Can you explain this answer?

Dr Manju Sen answered
Reduction potential means to accept electrons to reduce oneself.
 A + e- → A- ∆Ereduction = +ve value
Since, the reduction potential is negative, it means that the reaction will reverse to make ∆E value +ve. So the reaction becomes,
A → A+ + e- 
This becomes oxidation of A. So oxidation of A will be easy. 

The reduction potential of an element A is 1.71 V. What can be concluded from this?
  • a)
    A will lose electrons easily
  • b)
    A will undergo reduction easily
  • c)
    A will undergo oxidation easily
  • d)
    A will be a good reducing agent
Correct answer is option 'B'. Can you explain this answer?

Rajeev Saxena answered
The standard reduction potential is the tendency for a chemical species to be reduced, and is measured in volts at standard conditions. The more positive the potential is the more likely it will be reduced. Hence, A will undergo reduction easily.

In an electrolytic cell current flows from -
  • a)
    Cathode to anode in outer circuit
  • b)
    Anode to cathode outside the cell
  • c)
    Cathode to anode inside the cell 
  • d)
    Anode to cathode inside the cell
Correct answer is option 'A'. Can you explain this answer?

Krishna Iyer answered
In an electrolytic cell, current flows from cathode to anode in outer circuit and in daniell cell, it is the reverse direction of flow of current from anode to cathode in outer circuit.

 Stronger the oxidizing agent, greater is the:
  • a)
    Reactivity
  • b)
    Ionic behaviour
  • c)
    Oxidation potential
  • d)
    Reduction potential
Correct answer is option 'D'. Can you explain this answer?

Rajeev Saxena answered
Lithium is strongest Reducing agent because of lowest standard reduction potential. When something is oxidized, it reduces another substance, becoming a reducing agent. Hence lithium is the strongest reducing agent. remember, Li is the strongest reducing agent and F is the strongest oxidizing agent!

 Kohlrausch’s Law shows that:
  • a)
    at infinite dilution the ionic conductivity of ions is additive.
  • b)
    at infinite dilution the ionic conductivity of all the ions of the electrolyte become equal.
  • c)
    at infinite dilution the concentration of the electrolyte becomes unity.
  • d)
    at infinite dilution the concentration of ions increases.
Correct answer is option 'A'. Can you explain this answer?

Preeti Khanna answered
The correct answer is option A
Kohlrausch's law states that the equivalent conductivity of an electrolyte at infinite dilution is equal to the sum of the conductances of the anions and cations. If a salt is dissolved in water, the conductivity of the solution is the sum of the conductances of the anions and cations.
Hence, at infinite dilution the ionic conductivity of ions is additive.

In the equation, ΔG° = – nF E° cell ; F is:
  • a)
    Boltzmann constant
  • b)
    Faraday’s constant
  • c)
    Gas constant
  • d)
    Universal gas constant
Correct answer is option 'B'. Can you explain this answer?

Nandini Iyer answered
The correct answer is Option B.
The relationship between ΔGo and Eo is given by the following equation: ΔGo=−nFEo. Here, n is the number of moles of electrons and F is the Faraday constant.

The electrode potential measures the :
  • a)
    tendency of a cell reaction to occur
  • b)
    current carried by an elelctrode
  • c)
    tendency of the electrode to gain or lose electrons
  • d)
    difference in the ionisation of electrode and metal ion
Correct answer is option 'C'. Can you explain this answer?

Nandini Patel answered
The tendency of an electrode to lose or gain electrons when it is in contact with its own ions in solution is called electrode potential. 
Since the tendency to lose electrons means also the tendency to get oxidised, this tendency is called oxidation potential. Similarly, the tendency to gain electrons means the tendency to get reduced. Hence this tendency is called reduction potential. 

 In an electrochemical cell, the electrode having a lower reduction potential will act as:
  • a)
    Salt bridge
  • b)
    Electrolyte
  • c)
    Anode
  • d)
    Cathode
Correct answer is option 'C'. Can you explain this answer?

Sargam Singh answered
A substance with lower reduction potential has more tendency to oxidize .in a electrochemical cell anode performs oxidation reaction hence the electrode will function as a anode

During electrolysis, the reaction that takes place at cathode is:
  • a)
    Hydrolysis
  • b)
    Reduction
  • c)
    Oxidation
  • d)
    Neutralization
Correct answer is option 'B'. Can you explain this answer?

Rajat Patel answered
The electrode at which oxidation takes place is known as the anode, while the electrode at which reduction take place is called the cathode. If you see galvanic cell reduction take place at the left electrode, so the left one is the cathode. Oxidation takes place at the right electrode, so the right one is the anode.

 Gibbs free energy change for a cell reaction is positive what does it indicates?
  • a)
    cell will discharge easily
  • b)
    Cell reaction is spontaneous
  • c)
    Cell reaction is non spontaneous
  • d)
    Cell will work under standard conditions
Correct answer is option 'C'. Can you explain this answer?

Rajeev Saxena answered
No, reaction cannot be spontaneous (continue to happen) when the change in gibbs free energy is positive. ... For a spontaneous process to happen , the change in Gibbs free energy must be negative. A roaring bonfire is an example of a spontaneous reaction.

One of the simplest methods of preventing corrosion is to prevent the surface of the metallic object to come in contact with atmosphere. This can be done
  • a)
    by covering the surface with oil
  • b)
    by covering the surface with salt
  • c)
    by covering the surface with citric acid
  • d)
    by covering the surface with paint or by some chemicals
Correct answer is option 'D'. Can you explain this answer?

Preventing corrosion is essential to ensure the longevity and integrity of metallic objects. One of the simplest and most effective methods to prevent corrosion is by covering the surface of the object with paint or certain chemicals. This method creates a protective barrier between the metal surface and the atmosphere, preventing contact and thereby reducing the chances of corrosion.

Here is a detailed explanation of why covering the surface with paint or chemicals is an effective method of preventing corrosion:

1. Creation of a Barrier: By covering the surface of the metallic object with paint or chemicals, a physical barrier is created between the metal and the surrounding atmosphere. This barrier prevents the metal from coming into direct contact with oxygen, moisture, and other corrosive elements present in the air.

2. Protection from Moisture: Moisture is one of the primary causes of corrosion. When metal comes into contact with moisture, it undergoes a chemical reaction known as oxidation, leading to the formation of rust. By covering the surface, the paint or chemicals act as a waterproof layer, preventing moisture from reaching the metal surface and reducing the chances of corrosion.

3. Prevention of Oxygen Exposure: Oxygen is another key component in the corrosion process. By covering the surface, the paint or chemicals act as a barrier, preventing oxygen from reaching the metal surface. This helps in inhibiting the oxidation reaction and reducing the chances of corrosion.

4. Chemical Protection: Some paints and chemicals used for covering the surface of metallic objects contain corrosion inhibitors. These inhibitors are chemicals that actively work to prevent or slow down the corrosion process. They form a protective layer on the metal surface, hindering the reaction between the metal and corrosive elements.

5. Flexibility and Ease of Application: Paints and chemicals offer the advantage of being flexible and easy to apply on different types of metal surfaces. They can be brushed, sprayed, or dipped, allowing for complete coverage and protection against corrosion.

It is important to note that the choice of paint or chemical coating depends on the specific requirements of the metal object, the environment it will be exposed to, and the type of corrosion it is susceptible to. Consulting with experts or conducting thorough research is recommended to ensure the most suitable protective coating is applied.

 During electrolysis, the reaction that takes place at anode is:
  • a)
    Reduction
  • b)
    Neutralization
  • c)
    Hydrolysis
  • d)
    Oxidation
Correct answer is option 'D'. Can you explain this answer?

Rajat Patel answered
Oxidation takes place at the right electrode, so the right one is the anode. While in electrolytic cell reduction takes place at the right electrode, so right one is the cathode. Oxidation takes place at the left electrode, so the left one is the anode.

For the following cell with hydrogen electrodes at two different  pressure pand p
 emf is given by
  • a)
  • b)
  • c)
  • d)
Correct answer is option 'B'. Can you explain this answer?

Krishna Iyer answered
For SHE E°SHE = 0.00 V
Oxidation at anode (left)

Reduction at cathode (right) 
Net
This is the type of the cell in which electrodes at different pressures are dipped in same electrolyte and connectivity is made by a salt-bridge.
Reaction Quotient (Q) 
∵ 

 At equilibrium:
  • a)
    Cell potential’ E cell‘ becomes zero
  • b)
    Equilibrium constant becomes equal to electrode potential
  • c)
    Equilibrium constant becomes zero
  • d)
    Cell potential ‘E cell‘ becomes unity
Correct answer is option 'A'. Can you explain this answer?

Ayush Joshi answered
E cell is 0 in equilibrium that is E cathode becomes equal to E anode ………. ... So E cell is zero at equilibrium that is when the E(cathode) becomes equal to E(anode). E deg cell is zero in the concentration cell when both the electrodes are of the same metal.

Chapter doubts & questions for Electrochemistry - Chemistry CUET UG Mock Test Series 2026 2025 is part of NEET exam preparation. The chapters have been prepared according to the NEET exam syllabus. The Chapter doubts & questions, notes, tests & MCQs are made for NEET 2025 Exam. Find important definitions, questions, notes, meanings, examples, exercises, MCQs and online tests here.

Chapter doubts & questions of Electrochemistry - Chemistry CUET UG Mock Test Series 2026 in English & Hindi are available as part of NEET exam. Download more important topics, notes, lectures and mock test series for NEET Exam by signing up for free.

Top Courses NEET

Related NEET Content