All questions of 2012 for JEE Exam

Let f(x) = ax2 + bx + c, g(x) = px2 + qx + r, such that f(1) = g(1), f(2) = g(2) and f(3) – g(3) = 2. Then f(4) – g(4) is
  • a)
    4
  • b)
    5
  • c)
    6
  • d)
    7
Correct answer is option 'C'. Can you explain this answer?

Ashwini Pillai answered
= g(3).

From the given information, we can set up the following equations:

f(1) = a(1)2 + b(1) + c = p(1)2 + q(1) + r

f(2) = a(2)2 + b(2) + c = p(2)2 + q(2) + r

f(3) = a(3)2 + b(3) + c = p(3)2 + q(3) + r

Simplifying these equations, we get:

a + b + c = p + q + r (equation 1)

4a + 2b + c = 4p + 2q + r (equation 2)

9a + 3b + c = 9p + 3q + r (equation 3)

To find the values of a, b, and c, we can solve these equations simultaneously. Subtracting equation 1 from equation 2 and equation 3, we get:

3a + b = 3p + q (equation 4)

8a + 2b = 8p + 2q (equation 5)

Next, we subtract equation 4 from equation 5:

5a = 5p

Simplifying, we get:

a = p

Now we substitute this value of a into equation 4:

3p + b = 3p + q

Simplifying, we get:

b = q

Finally, we substitute the values of a and b into equation 1:

p + q + c = p + q + r

Simplifying, we get:

c = r

Therefore, we have found that a = p, b = q, and c = r. This means that f(x) = g(x) for all values of x.

The remainder obtained when 1!+2!+...+95! is divided by 15 is
  • a)
    14
  • b)
    3
  • c)
    1
  • d)
    0
Correct answer is option 'B'. Can you explain this answer?

Ritika Mehta answered
Starting from 5! all the other numbers are divisible by 15 since 15 will be a factor So 1! + 2! + 3! + 4! = 1 + 2 + 6 + 24 = 33 So the remainder on dividing 33 by 15 is 3.

The number of real values of for which the system of equations
x + 3y+5z = αx
5x+y+3z =α y    
3x+5y+z = αz
  • a)
    1
  • b)
    2
  • c)
    4
  • d)
    6
Correct answer is option 'A'. Can you explain this answer?

Sneha Sengupta answered


Understanding the System of Equations

- Given system of equations:
1. x + 3y + 5z = α
2. 5x + y + 3z = α
3. 3x + 5y + z = α

Analysis of the System

- To find the number of real values of α for which the system has a solution, we need to analyze the system of equations.
- We can represent the system in matrix form as AX = B, where A is the coefficient matrix, X is the variable matrix, and B is the constant matrix.

Determinant of Coefficient Matrix

- The determinant of the coefficient matrix A is given by |A| = -144.
- If |A| ≠ 0, then the system has a unique solution for any value of α.

Calculating the Determinant

- Since |A| ≠ 0, the system of equations has a unique solution for any value of α.
- Therefore, the number of real values of α for which the system has a solution is 1.

Therefore, the correct answer is option 'A'.

If 64, 27, 36 are the Pth , Qth and Rth terms of a G.P., then P + 2Q is equal to
  • a)
    R
  • b)
    2R
  • c)
    3 R
  • d)
    4 R
Correct answer is option 'C'. Can you explain this answer?

Nisha Sen answered
tP = 64,
tR = 36,
a . rP–1 = 64.............(1);
tQ = 27, a . rQ–1 = 27.............(2)
a . rR–1 = 36.............(3)
(2)2x (1)/(3)3 ; 2 Q + P = 3R

The equivalent  weight of K2Cr2O7 in acidic medium is expressed in terms of its molecular weight (M) as
  • a)
    M/3
  • b)
    M/4
  • c)
    M/6
  • d)
    M/7
Correct answer is option 'C'. Can you explain this answer?

Navya Hegde answered
Because k2Cr2O7 loses 6 elections. equivalent weight is the mass divided by the no of electrons lost or gained. that is why M/6 is the correct answer.

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