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All questions of January Week 2 for JEE Exam
If the Young’s apparatus is immersed in water, the effect on fringe width will- a)remain same
- b)decrease
- c)increase
- d)Cant say because the experiment cannot be carried in any other medium except air
Correct answer is option 'B'. Can you explain this answer?
If the Young’s apparatus is immersed in water, the effect on fringe width will
a)
remain same
b)
decrease
c)
increase
d)
Cant say because the experiment cannot be carried in any other medium except air
|
Kalyan Joshi answered |
Effect of Immersing Young's Apparatus in Water on Fringe Width
When the Young's apparatus is immersed in water, the effect on the fringe width can be explained as follows:
1. Refractive Index of Water: Water has a higher refractive index than air. This means that light passing through water will be bent more than in air.
2. Path Difference: Path difference is the difference in the distance traveled by two waves from the source to the point where they interfere with each other. When the apparatus is immersed in water, the path difference between the two waves will change due to the change in refractive index.
3. Decrease in Fringe Width: As the path difference changes, the interference pattern will also change. The fringe width will decrease because the change in the path difference will cause the interference pattern to become more spread out.
4. Explanation: The fringe width is inversely proportional to the square root of the refractive index. Since the refractive index of water is higher than air, the fringe width will decrease when the apparatus is immersed in water.
Conclusion
In conclusion, when the Young's apparatus is immersed in water, the fringe width will decrease due to the change in refractive index, which leads to a change in the path difference and the interference pattern.
When the Young's apparatus is immersed in water, the effect on the fringe width can be explained as follows:
1. Refractive Index of Water: Water has a higher refractive index than air. This means that light passing through water will be bent more than in air.
2. Path Difference: Path difference is the difference in the distance traveled by two waves from the source to the point where they interfere with each other. When the apparatus is immersed in water, the path difference between the two waves will change due to the change in refractive index.
3. Decrease in Fringe Width: As the path difference changes, the interference pattern will also change. The fringe width will decrease because the change in the path difference will cause the interference pattern to become more spread out.
4. Explanation: The fringe width is inversely proportional to the square root of the refractive index. Since the refractive index of water is higher than air, the fringe width will decrease when the apparatus is immersed in water.
Conclusion
In conclusion, when the Young's apparatus is immersed in water, the fringe width will decrease due to the change in refractive index, which leads to a change in the path difference and the interference pattern.
Two coherent sources produce a dark fringe when phase difference between the interfering waves is(n integer)- a)2π
- b)(2n – 1)π
- c)zero
- d)n
Correct answer is option 'B'. Can you explain this answer?
Two coherent sources produce a dark fringe when phase difference between the interfering waves is(n integer)
a)
2π
b)
(2n – 1)π
c)
zero
d)
n
|
Shruti Sarkar answered |
Dark fringes will be produced when there are destructive interference. The condition for that is the two waves should have a phase difference of an odd integral multiple of π.
Young’s double slit experiment is carried out using two bulbs instead of using two slits and one source. Then- a)Fringes will be elliptical
- b)No interference fringes will be observed
- c)Fringes will be dark
- d)The interference fringes will be colored
Correct answer is option 'B'. Can you explain this answer?
Young’s double slit experiment is carried out using two bulbs instead of using two slits and one source. Then
a)
Fringes will be elliptical
b)
No interference fringes will be observed
c)
Fringes will be dark
d)
The interference fringes will be colored
|
Rajesh Gupta answered |
We observe interference pattern when the size of the slits are comparable to the wavelength of light. But here, the size of the bulb is bigger than wavelength of light.
In Young’s double slit experiment, the distance between the two slits is halved and the distance of the screen from the slit is doubled. The fringe width will be- a)Will become four times
- b)Doubled
- c)Remain same
- d)Halved
Correct answer is option 'A'. Can you explain this answer?
In Young’s double slit experiment, the distance between the two slits is halved and the distance of the screen from the slit is doubled. The fringe width will be
a)
Will become four times
b)
Doubled
c)
Remain same
d)
Halved
|
Anaya Patel answered |
Fringe width β=λD/d
On d′=d/2, D′=2D
New fringe width β′= λD′/d′=4β
On d′=d/2, D′=2D
New fringe width β′= λD′/d′=4β
When viewed in white light, a soap bubble shows colours because of- a)Interference
- b)Scattering
- c)Dispersion
- d)Diffraction
Correct answer is option 'A'. Can you explain this answer?
When viewed in white light, a soap bubble shows colours because of
a)
Interference
b)
Scattering
c)
Dispersion
d)
Diffraction
|
Hansa Sharma answered |
When the light is incident on a soap bubble of certain thickness it constructively interferes for wavefronts which are in phase to produce white light and when the wavefronts are out of phase, they undergo destructive interference to produce a series of colors. Thus, interference is the reason.
In the Young’s double slit experiment, the distance of p th dark fringe from the central maximum is:- a)
- b)
- c)
- d)
Correct answer is option 'B'. Can you explain this answer?
In the Young’s double slit experiment, the distance of p th dark fringe from the central maximum is:
a)
b)
c)
d)
|
Neha Sharma answered |
Position of the pth dark fringe is at a distance of
y=(2p−1) (λD/2d) from the centre
where
λ: Wavelength
D: Distance between slits
d: slit width
y=(2p−1) (λD/2d) from the centre
where
λ: Wavelength
D: Distance between slits
d: slit width
In an interference experiment monochromatic light is replaced by white light, we will see:- a)uniform darkness on the screen
- b)a few coloured bands and then uniform illumination
- c)equally spaced white and dark bands
- d)uniform illumination on the screen
Correct answer is option 'B'. Can you explain this answer?
In an interference experiment monochromatic light is replaced by white light, we will see:
a)
uniform darkness on the screen
b)
a few coloured bands and then uniform illumination
c)
equally spaced white and dark bands
d)
uniform illumination on the screen
|
|
Arun Khanna answered |
Therefore if monochromatic light in Young's interference experiment is replaced by white light, then the waves of each wavelength form their separate interference patterns. The resultant effect of all these patterns is obtained on the screen. i.e., the waves of all colours reach at mid point M in same phase we will see.a few coloured bands and then uniform illumination
In Young’s double slit experiment, one slit is covered. The observed effect will be- a)intensities of the fringes will be reduced
- b)interference will not take place
- c)colored fringes will be produced
- d)dark fringes will be replaced by bright ones
Correct answer is option 'B'. Can you explain this answer?
In Young’s double slit experiment, one slit is covered. The observed effect will be
a)
intensities of the fringes will be reduced
b)
interference will not take place
c)
colored fringes will be produced
d)
dark fringes will be replaced by bright ones
|
Divyansh Kulkarni answered |
Adult fiction, the term "In Young" is not a commonly used phrase or concept. It is possible that you may be referring to a specific book or series that uses this term in a unique way, but without further information, it is difficult to provide a more specific answer. Can you please provide more context or information about what you are referring to?
Which of the following in conserved when light waves interfere?- a)Mass
- b)Amplitude
- c)Energy
- d)Intensity
Correct answer is option 'C'. Can you explain this answer?
Which of the following in conserved when light waves interfere?
a)
Mass
b)
Amplitude
c)
Energy
d)
Intensity
|
|
Rohan Singh answered |
A wave can transmit energy from one place to another.
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